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Chain Rule Questions

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A fort had provision of food for 150 men for 45 days. After 10 days, 25 men left the fort. The number of days for which the remaining food will last, is:


A29

B37

C42

D54

Answer: Option C

Explanation:

Lets assume remaining food will lost after x days.

Note: (u) means up arrow and (d) means down arrow.

(after 10 day 25 men left so remaining man will be 125 and 150 men was for 35 days)

Men Days
----------------
150(u) 35(d)
125 x

150/125 = x/35
=> x = (150*35)/125
=> x = 6*7
=> x = 42

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10 men, working 6 hours a day can complete a work in 18 days. How many hours a day must 15 men work to complete the work in 12 days ?


A4 hours a day

B5 hours a day

C6 hours a day

D7 hours a day

Answer: Option C

Explanation:

Lets assume x hrs required to complete the work in 12 days.

Note: (u) means up arrow and (d) means down arrow.

Men hrs days
-----------------------
10(u) 6(u) 18(d)
15 12 x

(10/15 * 6/12 )= x/18
x = (10 * 6 * 18)/(15 * 12)
=>x=6 hrs/day

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If 16 men working 7 hours day can plough a field in 48 days, in how many days will 14 men working 12 hours a clay plough the same field ?


A46

B32

C35

D30

Answer: Option B

Explanation:

Lets assume x days required to plough the same field.

Note: (u) means up arrow and (d) means down arrow.

Men hrs days
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16 (u) 7 (u) 48 (d)
14 12 x

(16/14 * 7/12 )= x/48
x = (16 * 7 * 48)/(14 * 12)
= (16*2)
=32

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A wheel that has 6 cogs is meshed with a larger wheel of 14 cogs. When the smaller wheel has made 21 revolutions, then the number of revolutions made by the larger wheel is:


A4

B9

C12

D49

Answer: Option B

Explanation:

Lets assume x revolutions made by larger wheel.

Note: (u) means up arrow and (d) means down arrow.

cogs revolutins
------------------
6(u) 21
14 x 1

6/14 = x/21
=> x = (6/14 * 21)
=> x = 9 rev.

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If 20 men can build a wall 56 meters long in 6 days , what length of a similar wall can be built by 35 men in 3 days?


A46

B47

C48

D49

Answer: Option D

Explanation:

Lets assume x meters length wall will be made.

Note: (u) means up arrow and (d) means down arrow.

men wall days
---------------------
20(d) 56(d) 6(d)
35 x 3

(35/20 * 3/6) = x/56
=> x = (35/20 * 3/6 * 56)
=> x = 49 meters.

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Some persons can do a piece of work in 12 days. Two times the number of such persons will do half of that work in


A6 days

B12 days

C4 days

D3 days

Answer: Option D

Explanation:

Lets assume x day need to do half work

Note: (u) means up arrow and (d) means down arrow.

persons work days
-----------------------------
1(u) 1(d) 12(d)
2 1/2 x

(1/2 * 1/2) = x/12
=> x = 1/4 * 12 = 3 days.

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A certain number of men can finish a piece of work in 100 days. If there were 10 men less, it would take 10 days more for the work to be finished. How many men were there originally?


A75

B82

C100

D110

Answer: Option D

Explanation:

Lets assume x men originally.

Note: (u) means up arrow and (d) means down arrow.

men work days
---------------------
x(u) 1(d) 100(d)
(x-10) 1 110


x/(x-10)*1 = 110/100
=> 100x = 110x-1100
=> 10x = 1100
=> x = 110

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In a dairy farm, 40 cows eat 40 bags of husk in 40 days. In how many days one cow will eat one bag of husk?


A1

B1/40

C40

D80

Answer: Option C

Explanation:

Lets assume one bag will go x days.

Note: (u) means up arrow and (d) means down arrow.

cows bags days
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40(u) 40(d) 40(d)
1 1 x

40 *1/40 = x/40
=> x = 40 days.

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A contractor undertakes to do a piece of work in 40 days. He engages 100 men at the beginning and 100 more after 35 days and completes the work in stipulated time. If he had not engaged the additional men, how many days behind schedule would it be finished?


A3

B5

C6

D9

Answer: Option B

Explanation:

[(100 * 35)+(200 * 5)] men can finish the work in 1 day

therefore 4500 men can finish the work in 1 day.
100 men can finish it in [4500/100] = 45 days.

=> 5 days behind Schedule

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39 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work?


A10

B13

C14

D15

Answer: Option B

Explanation:

Lets assume x days required to complete the work.

Note: (u) means up arrow and (d) means down arrow.

persons hrs. days
---------------------
39(u) 5(u) 12(d)
30 6 x

(39/30 * 5/6) = x/12
=> x = (39/30 * 5/6 ) * 12
=> x = 13 days.

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