More men, more length built (Direct).
Less days, less length built (Direct).
Men 20:35 :: 56: x
Similarly, days 6:3 :: 56: x.
Therefore, 20*6*x= 35*3*56 or x= 49.
Hence, the required length= 49m.
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If 9 engines consume 24 metric tonnes of coal, when each is working 8 hours a day; how much coal will be required for 8 engines, each running 13 hours a day, it being given that 3 engines of the former type consume as much as 4 engines of latter type.
Less engines, less coal consumed (direct)
More working hours, more coal consumed (direct)
If 3 engines of former type consume 1 unit, then 1 engine will consume 1/3 unit.
If 4 engines of latter type consume 1 unit, then 1 engine will consume 1/4 unit.
Less rate of consumption, less coal consumed (direct).
Therefore, number of engines 9:8 :: 24:x
Working hours 8:13 :: 24:x
Rate of consumption 1/3:1/4 :: 24:x.
9*8*1/3*x= 8*13*1/4*24 or x= 26.
So, required consumption of coal 26 metric tonnes.
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A garrison of 3300 men had provisions for 32 days, when given at the rate of 850 gms per head. At the end of 7 days, reinforcement arrives and it was found that the provisions will last 17 days more, when given at the rate of 825gms per head. What is the strength of the reinforcement?
The problem becomes:
3300 men taking 850gms per head have provisions for (32-7) or 25 days. How many men taking 825gms each have provisions for 17 days?
Less ration per head, more men (indirect).
Less days, more men (indirect)
Ration 825:850::3300:x
Days 17:25::3300:x
Therefore, 825*17*x= 850*25*3300 or x= 5000.
So, strength of reinforcement = 5000-3300 = 1700.
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A contract is to be completed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days 4/7 of the work is completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours a day?
Remaining work = 1-4/7 =3/7.
Remaining period = (46-33) days =13 days.
Less work, less men (direct)
Less days, more men (indirect).
More hours per day, less men (indirect)
Therefore, work 4/7:3/7 ::117/x
Days 13:33 :: 117/x
Hrs/day 9:8:: 117/x
Therefore, 4/7*13*9*x= 3/7*33*8*117 or x= 198.
Therefore, additional men to be employed =(198-117) = 81.
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2 oranges, 3 bananas and 4 apples cost Rs.15. 3 oranges 2 bananas 1 apple costs Rs.10. what is the cost of 3 oranges, 3 bananas and 3 apples?
Lets assume orange, banana and apple cost is x, y and z respectively.
So, 2 orange + 3 banana + 4 apple =(2x+ 3y + 4z) = 15 -------- (1)
and 3 orange + 2 banana + 1 apple) = (3x+2y+z) = 10 ---------(2)
so from eq. (1) and (2)
5 (orange + banana + apple ) = 25
=> (orange + banana + apple ) = 5
so 3 orange + 3 banana + 3 apple = 3 * 5 = Rs. 15
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A college starts from 10 AM continues till 1:30 PM. In this duration there are five periods. If 5 minutes are provided before each period to leave the room and enter the other, then what is the duration of each period?
Let 1 man's 1 day's work = x and 1 woman's 1 day's work = y.
Then, 4x + 6y = 1/8 and 3x + 7y = 1/10.
Solving the two equations, we get: x = 11/400, y = 1/400.
So, 1 woman's 1 day's work = 1/400.
10 women's 1 day's work = 1/400 x 10 = 1/40.
Hence, 10 women will complete the work in 40 days.
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A garrison of 3300 men has provisions for 32 days, when given at a rate of 850 grams per head. At the end of 7 days a reinforcement arrives and it was found that now the provisions will last 8 days less, when given at the rate of 825 grams per head.How, many more men can it feed?
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