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# Chain Rule Questions

Home > Quantitative Aptitude > Chain Rule > General Questions
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4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 8 mat-weavers in 8 days?

A16

B12

C8

D4

Explanation:

Lets assume x mats would be weave in 8days.

Note: (u) means up arrow and (d) means down arrow.

weavers mats days
----------------------------
4(d) 4(d) 4(d)
8 x 8

(8/4* 8/4) = x/4
=> x = 4*4 = 16 mats.

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Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

A648

B1800

C2700

D10800

Explanation:

Lets assume x bottle produce in 1 minutes.

Note: (u) means up arrow and (d) means down arrow.

machines bottles/min
----------------
6(d) 270(d)
10 x

10/6 = x/270
=> x = (270 * 10)/6
=> x = 450/min
Total produce in 4 min = 450*4 = 1800

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A fort had provision of food for 150 men for 45 days. After 10 days, 25 men left the fort. The number of days for which the remaining food will last, is:

A29

B37

C42

D54

Explanation:

Lets assume remaining food will lost after x days.

Note: (u) means up arrow and (d) means down arrow.

(after 10 day 25 men left so remaining man will be 125 and 150 men was for 35 days)

Men Days
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150(u) 35(d)
125 x

150/125 = x/35
=> x = (150*35)/125
=> x = 6*7
=> x = 42

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10 men, working 6 hours a day can complete a work in 18 days. How many hours a day must 15 men work to complete the work in 12 days ?

A4 hours a day

B5 hours a day

C6 hours a day

D7 hours a day

Explanation:

Lets assume x hrs required to complete the work in 12 days.

Note: (u) means up arrow and (d) means down arrow.

Men hrs days
-----------------------
10(u) 6(u) 18(d)
15 12 x

(10/15 * 6/12 )= x/18
x = (10 * 6 * 18)/(15 * 12)
=>x=6 hrs/day

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If 16 men working 7 hours day can plough a field in 48 days, in how many days will 14 men working 12 hours a clay plough the same field ?

A46

B32

C35

D30

Explanation:

Lets assume x days required to plough the same field.

Note: (u) means up arrow and (d) means down arrow.

Men hrs days
------------------
16 (u) 7 (u) 48 (d)
14 12 x

(16/14 * 7/12 )= x/48
x = (16 * 7 * 48)/(14 * 12)
= (16*2)
=32

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A wheel that has 6 cogs is meshed with a larger wheel of 14 cogs. When the smaller wheel has made 21 revolutions, then the number of revolutions made by the larger wheel is:

A4

B9

C12

D49

Explanation:

Lets assume x revolutions made by larger wheel.

Note: (u) means up arrow and (d) means down arrow.

cogs revolutins
------------------
6(u) 21
14 x 1

6/14 = x/21
=> x = (6/14 * 21)
=> x = 9 rev.

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If 20 men can build a wall 56 meters long in 6 days , what length of a similar wall can be built by 35 men in 3 days?

A46

B47

C48

D49

Explanation:

Lets assume x meters length wall will be made.

Note: (u) means up arrow and (d) means down arrow.

men wall days
---------------------
20(d) 56(d) 6(d)
35 x 3

(35/20 * 3/6) = x/56
=> x = (35/20 * 3/6 * 56)
=> x = 49 meters.

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Some persons can do a piece of work in 12 days. Two times the number of such persons will do half of that work in

A6 days

B12 days

C4 days

D3 days

Explanation:

Lets assume x day need to do half work

Note: (u) means up arrow and (d) means down arrow.

persons work days
-----------------------------
1(u) 1(d) 12(d)
2 1/2 x

(1/2 * 1/2) = x/12
=> x = 1/4 * 12 = 3 days.

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A certain number of men can finish a piece of work in 100 days. If there were 10 men less, it would take 10 days more for the work to be finished. How many men were there originally?

A75

B82

C100

D110

Explanation:

Lets assume x men originally.

Note: (u) means up arrow and (d) means down arrow.

men work days
---------------------
x(u) 1(d) 100(d)
(x-10) 1 110

x/(x-10)*1 = 110/100
=> 100x = 110x-1100
=> 10x = 1100
=> x = 110

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In a dairy farm, 40 cows eat 40 bags of husk in 40 days. In how many days one cow will eat one bag of husk?

A1

B1/40

C40

D80

Explanation:

Lets assume one bag will go x days.

Note: (u) means up arrow and (d) means down arrow.

cows bags days
---------------------
40(u) 40(d) 40(d)
1 1 x

40 *1/40 = x/40
=> x = 40 days.

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