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An intelligent trader travels from 1 place to another carrying 3 sacks having 30 coconuts each. No sack can hold more than 30 coconuts. On the way, he passes through 30 checkpoints and on each checkpoint he has to give 1 coconut for each sack he is carrying. Maximum how many coconuts he can save when he reaches the last checkpoint.
Explanation :
No Best Answer on this question yet!Asked In : Capgemini
for first 10 check posts one bag will get empty 30+30+30-3*10=60
for next 15 check posts another one bag will get empty 30+30-2*15=30
for the remaining 5 check posts he will give one coconut 30-1*5=25
thus finally he can save 25 coconuts at the last check point