Program Discussion :: Basics
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Write a program to find the given number is even or odd.
INPUT: 14
OUTPUT: Even
INPUT: 13
OUTPUT: Odd
Answer:
#include
using namespace std;
int main()
{
int n;
cout > n;
if ( n % 2 == 0)
cout
Asked In ::
Language:
Amit
20 Jun, 2017 11:23 PM
<!DOCTYPE html>
<html>
<body>
<?php
function even_odd()
{
$operator="+";
$firstNumber=5; $secondNumber=10;
switch($operator)
{
case '+':
$ans=$firstNumber+$secondNumber;
echo "operator is + and output is: " . $ans;
break;
case '-':
echo "operator is - and output is: " .$firstNumber+$secondNumber;
break;
case '*':
echo "operator is * and output is: " .$firstNumber+$secondNumber;
break;
case '/':
echo "operator is / and output is: " .$firstNumber+$secondNumber;
break;
default :
"Error! operator is not correct";
}
}
even_odd();
?>
</body>
</html>
Language:
Shyam
7 Jul, 2017 9:30 AM
#include <stdio.h>
int main()
{
int number;
printf("Enter an integer: ");
scanf("%d", &number);
// True if the number is perfectly divisible by 2
if(number % 2 == 0)
printf("%d is even.", number);
else
printf("%d is odd.", number);
return 0;
}
Language:
Nick
7 Jul, 2017 9:30 AM
#include <iostream>
using namespace std;
int main()
{
int n;
cout << "Enter an integer: ";
cin >> n;
if ( n % 2 == 0)
cout << n << " is even.";
else
cout << n << " is odd.";
return 0;
}
Language:
Siddhartha Paul
19 Jun, 2019 2:16 PM
import java.util.*;
public class EvenOdd
{
public static void main(String []args)
{
int num;
Scanner sc=new Scanner(System.in);
System.out.println("Enter a number: ");
num=sc.nextInt();
if(num % 2 == 0)
System.out.println(num+" is even!");
else
System.out.println(num+" is odd!");
}
}