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# Flow Chart Questions

Home > Logical Reasoning > Flow Chart > General Questions
NA
SHSTTON
295
Solv. Corr.
418
Solv. In. Corr.
713
Attempted
0 M:39 S
Avg. Time

1 / 5

Study the flow chart give below and the questions that follow

Question: At the end of the flow chart the number placed in which of the following boxes will remain unchanged

ABox 3

BBox 10

CBox 2

DBox 7

Explanation:

ANSWR d)Box 7
Explanation :

In instruction 1, Box 10 is modified;
In instruciton 3, Box 2 is modified;
and in instruction 5, Box 3 gets mofied;

Therefore out of given options only Box 7 remains unchanged.

Workspace

NA
SHSTTON
461
Solv. Corr.
327
Solv. In. Corr.
788
Attempted
1 M:33 S
Avg. Time

2 / 5

Is the following statement True or False

Statement:
If the condition in Step C updates the value in Box 3 instead of Box 2, then the flow chart will enter into infinite loop

ATRUE

BFALSE

CCannot be determined

Explanation:

Explanation.

even if Box 3 is updated instead of Box 2 in instruction C,

In instruction D, Number in Box 2 is compared with Box 7,

and the value is anyway greater, so the result is YES there and thus exiting and finishing the loop.

Workspace

NA
SHSTTON
249
Solv. Corr.
296
Solv. In. Corr.
545
Attempted
6 M:23 S
Avg. Time

3 / 5

Study the flow chart give below and the questions that follow.

What number is now in Box 8?
What number is now in box 11?

A11, 5

B11, 2

C8, 6

D11, 9

Explanation:

None of the available answers is the correct:

step 1  : ins 1  : 2[Box 11] 3 = 5[Box 11]

step 2  : ins 2  : 8[Box 1] -> 8[Box 10]

step 3  : ins 3  : is 1 an odd number? YES

step 4  : ins 4  : go to instruction 6[Box 2[Box 6]]

step 5  : ins 6  : 4[Box 5] 5[Box 11] = 9[Box 11]

step 6  : ins 7  : change ins2: [Box 1 1] -> [Box 10 - 1]

step 7  : ins 8  : 9 < 8[Box 1] ? NO

step 8  : ins 9  : go to instruction 2

step 9  : ins 2  : 6[Box 2] -> 6[Box 9]

step 10 : ins 3  : is 2 an odd number? NO

step 11 : ins 6  : 4[Box 5] 9[Box 11] = 13[Box 11]

step 12 : ins 7  : change ins2: [Box 2 1] -> [Box 9 - 1]

step 13 : ins 8  : 8 < 8[Box 1] ? NO

step 14 : ins 9  : go to instruction 2

step 15 : ins 2  : 5[Box 3] -> 5[Box 8]

step 16 : ins 3  : is 3 an odd number? YES

step 17 : ins 4  : go to instruction 6[Box 2[Box 6]]

step 18 : ins 6  : 4[Box 5] 13[Box 11] = 17[Box 11]

step 19 : ins 7  : change ins2: [Box 3 1] -> [Box 8 - 1]

step 20 : ins 8  : 7 < 8[Box 1] ? YES

ANSWER: 5[Box 8] and 17[Box 11]

Workspace

NA
SHSTTON
93
Solv. Corr.
366
Solv. In. Corr.
459
Attempted
2 M:19 S
Avg. Time

4 / 5

Study the flow chart give below and the questions that follow.

The purpose of the following chart is to double the number in each of the boxes 2, 4, 6, 8 and 10.
In order to accomplish exactly this - no more and no less - What is the smallest number Which may be in box 1 ?

A19

B15

C9

D11

Explanation:

Correct answer is Option D - 11

FYI "box number" is not same as number in the "number in the box"

In above case during last iteration, the second box number is 12 which should be greater than number in the box 1. ie it should be 11.

[Box 12] > 11[Box 1]

Workspace

NA
SHSTTON
64
Solv. Corr.
287
Solv. In. Corr.
351
Attempted
4 M:51 S
Avg. Time

5 / 5

Study the flow chart give below and the questions that follow.

A19

B15

C11

D14

Explanation:

Instruction 1 : 5 [Box 4] + 2 [Box 10] = 3 [Box 1]
Instruction 2 : 3 [Box 1] + 3 [Box 6] = 6 [Box 1]
Instruction 3 : IS 6 [Box 1] evenly divisible by 4? = NO
Instruction 4 : 6 [Box No.] + 3[Box 6] = 9 [Box No.]
Instruction 5 : IS 13 [Box 2] > 9[Box No.] ? = YES
Instruction 6 : 7[Box 9] - 1 = 6 [Box 9]
Instruction 2 : 6 [Box 1] + 6 [Box 9] = 12 [Box 1]
Instruction 3 : IS 12 [Box 1] evenly divisible by 4? = NO
Instruction 4 : 9[Box No.] + 3[Box 6] = 12[Box No.]
Instruction 5 : IS 13 [Box 2] > 12 [Box No.] ? = YES
Instruction 6 : 6 [Box 9] -1 = 5 [Box 9]
Instruction 2 : 12 [Box 1] + 2 {Box 12] =14[Box 1]
Instruction 3 : IS 14 [Box 1] evenly divisible by 4? = NO
Instruction 4 : 12 [Box No.] + 3 [Box 6] = 15 [Box No.]
Instruction 5 : IS 13 [Box 2] > 15 [Box No.] ? = NO

Workspace

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