Flow Chart Questions

Answer: Option D

ANSWR d)Box 7
Explanation :

In instruction 1, Box 10 is modified;
In instruciton 3, Box 2 is modified;
 and in instruction 5, Box 3 gets mofied;

Therefore out of given options only Box 7 remains unchanged.

Answer: Option B

Answer b)FALSE

Explanation.

even if Box 3 is updated instead of Box 2 in instruction C,

In instruction D, Number in Box 2 is compared with Box 7,

and the value is anyway greater, so the result is YES there and thus exiting and finishing the loop.

Answer: Option D

The answer is E.

The instruction 1 gets modified as long as the condition becomes false.

Step 1 defines (on the first occurance) and executes the instruction

Step 2 modifies the instruction

Step 3 does an evaluation

On each loop, the box 2, 4, 6, 8, 10... gets filled with 0. We need to limit it until 6 only.

When the last box count becomes 6, we need to execute the instruction. So, box 3 should not have 6. After executing instruction, it updates the box number to 8. Here, we need to break. 

So, box 3 should contain 8.

Answer: Option D

None of the available answers is the correct:

step 1  : ins 1  : 2[Box 11] 3 = 5[Box 11]

step 2  : ins 2  : 8[Box 1] -> 8[Box 10]

step 3  : ins 3  : is 1 an odd number? YES

step 4  : ins 4  : go to instruction 6[Box 2[Box 6]]

step 5  : ins 6  : 4[Box 5] 5[Box 11] = 9[Box 11]

step 6  : ins 7  : change ins2: [Box 1 1] -> [Box 10 - 1]

step 7  : ins 8  : 9 < 8[Box 1] ? NO

step 8  : ins 9  : go to instruction 2

step 9  : ins 2  : 6[Box 2] -> 6[Box 9]

step 10 : ins 3  : is 2 an odd number? NO

step 11 : ins 6  : 4[Box 5] 9[Box 11] = 13[Box 11]

step 12 : ins 7  : change ins2: [Box 2 1] -> [Box 9 - 1]

step 13 : ins 8  : 8 < 8[Box 1] ? NO

step 14 : ins 9  : go to instruction 2

step 15 : ins 2  : 5[Box 3] -> 5[Box 8]

step 16 : ins 3  : is 3 an odd number? YES

step 17 : ins 4  : go to instruction 6[Box 2[Box 6]]

step 18 : ins 6  : 4[Box 5] 13[Box 11] = 17[Box 11]

step 19 : ins 7  : change ins2: [Box 3 1] -> [Box 8 - 1]

step 20 : ins 8  : 7 < 8[Box 1] ? YES

ANSWER: 5[Box 8] and 17[Box 11]

Answer: Option A

Assume [Box 1]= 19

Instruction 1: 2[Box 2] 2[Box 2] = 4[Box 2​]

Instruction 2: [Box 2] 2 = [Box 4] // increase box num from 2 to 4.

Instruction 3: IS [Box 1] 19 < [Box 2] 4  NO

Instruction 1: 4[Box 4] 4[Box 4] = 8[Box 4​]

Instruction 2: [Box 4] 2 = [Box 6]

Instruction 3: IS [Box 1] 19 < [Box 4] 8  NO

Instruction 1: 6[Box 6] 6[Box 6] = 12[Box 6]

Instruction 2: [Box 6] 2 = [Box 8] 

Instruction 3: IS [Box 1] 19 < [Box 6]12  NO

Instruction 1: 8[Box 8] 8[Box 8] = 16[Box 8​]

Instruction 2: [Box 8] 2 = [Box 10] 

Instruction 3: IS [Box 1] 19 < [Box 8]16  NO

Instruction 1: 10[Box 10] 10[Box 10] = 20[Box 10​]

Instruction 2: [Box 10] 2 = [Box 12]

Instruction 3: IS [Box 1] 19 < [Box 10] 20  YES

END

SO the ans should be 19//option A

// If you put [Box 1] = 9 then instruction end @ Instruction 3: IS [Box 1] 9 < [Box 6]12  Yes

//  If you put [Box 1] = 11 then instruction end @ Instruction 3: IS [Box 1] 11 < [Box 6]12  Yes

// If you put [Box 1] = 15 then instruction end @ Instruction 3: IS [Box 1] 15 < [Box 8]16  Yes

As per mention above we have to double 2,4,6,8,10 value...so loop never ends before updating upto

[Box 10] thats why our ans become 19

Answer: Option A

Instruction 1 : 0 [Box 3] + 1 [Box 11] = 1 [Box 11]
Instruction 2 : 1 [Box 1] + 1 [Box 11] = 2 [Box 5]
Instruction 3 : 3 [Box 4] * 3 [Box 4] = 9 [Box 4]
Instruction 4 : IS 2 [Box 5] = 6 [Box 10] ? NO
Instruction 5 : 9 [Box 4] - 6 = 3 [Box 4]
Instruction 6 : 2 [Box 5] + 2 [Box 2] = 4 [Box 5]
Instruction 3 : 3 [Box 4] * 3 [Box 4] = 9 [Box 4]
Instruction 4 : IS 4 [Box 5] = 6 [Box 10] ? NO
Instruction 5 : 9 [Box 4] - 6 = 3 [Box 4]
Instruction 6 : 4 [Box 5] + 2 [Box 2] = 6 [Box 5]
Instruction 3 : 3 [Box 4] * 3 [Box 4] = 9 {box 4]
Instruction 4 : IS 6 [Box 5] = 6 [Box 10] ? YES
Instruction 7 : 24 [Box 7] - 6 [Box 5] = 18 [Box 8]
Instruction 8 : 9 [Box 4] + 18 [Box 8] = 27 [Box 6]
ANSWER Box 6 = 27

Answer: Option D

Instruction 1 : 5 [Box 4] + 2 [Box 10] = 3 [Box 1]
Instruction 2 : 3 [Box 1] + 3 [Box 6] = 6 [Box 1]
Instruction 3 : IS 6 [Box 1] evenly divisible by 4? = NO
Instruction 4 : 6 [Box No.] + 3[Box 6] = 9 [Box No.]
Instruction 5 : IS 13 [Box 2] > 9[Box No.] ? = YES
Instruction 6 : 7[Box 9] - 1 = 6 [Box 9]
Instruction 2 : 6 [Box 1] + 6 [Box 9] = 12 [Box 1]
Instruction 3 : IS 12 [Box 1] evenly divisible by 4? = NO
Instruction 4 : 9[Box No.] + 3[Box 6] = 12[Box No.]
Instruction 5 : IS 13 [Box 2] > 12 [Box No.] ? = YES
Instruction 6 : 6 [Box 9] -1 = 5 [Box 9]
Instruction 2 : 12 [Box 1] + 2 {Box 12] =14[Box 1]
Instruction 3 : IS 14 [Box 1] evenly divisible by 4? = NO
Instruction 4 : 12 [Box No.] + 3 [Box 6] = 15 [Box No.]
Instruction 5 : IS 13 [Box 2] > 15 [Box No.] ? = NO
ANSWER Box 1 = 14

Answer: Option B

If Box 4 = 7
Instruction 1 : 5[ Box 1] - 5 [Box 1] = 0 [Box 3]
Instruction 2 : 0 [Box 3] + 3 {Box 9] = 3 [Box 3]
Instruction 3 : IS 7[Box 4] > 9[Box No.] ? = NO
Instruction 4 : 9 [Box No.] - 1 = 8 [Box No.]
Instruction 2 : 3 [Box 3] + 7 [Box 8] = 10 [Box 3]
Instruction 3 : IS 7[Box 4] > 8[Box No.] ? = NO
Instruction 4 : 8 [Box No.] - 1 = 7 [Box No.]
Instruction 2 : 10 [Box 3] + 6 [Box 7] = 16 [Box 3]
Instruction 3 : IS 7[Box 4] > 7[Box No.] ? = NO
Instruction 4 : 7 [Box No.] - 1 = 6 [Box No.]
Instruction 2 : 16 [Box 3] + 8 [Box 6] = 24 [Box 3]
Instruction 3 : IS 7[Box 4] > 6[Box No.] ? = YES
ANSWER Box 4 = 7

Answer: Option C

Assume Box 2 has number 2, Box 3 has number 3 and so on.
And Box 1 has number 10
Instruction 1 : 2 [Box 2] + 2[Box 2] = 4[Box 2]
Instruction 2 : 2 [Box No.] + 2 = 4 [Box No.]
Instruction 3 : IS 10 [Box 1] < 4 [Box No.] ? NO
Instruction 1 : 4 [Box 4] + 4{Box 4] = 8[Box 4]
Instruction 2 : 4 [Box No.] + 2 = 6 [Box No.]
Instruction 3 : IS 10 [Box 1] < 6 [Box No.] ? NO
Instruction 1 : 6 [Box 6] + 6 [Box 2] = 12[Box 6]
Instruction 2 : 6 [Box No.] + 2 = 8 [Box No.]
Instruction 3 : IS 10 [Box 1] < 8 [Box No.] ? NO
Instruction 1 : 8 [Box 8] + 8 [Box 8] = 16[Box 8]
Instruction 2 : 8 [Box No.] + 2 = 10 [Box No.]
Instruction 3 : IS 10 [Box 1] < 10 [Box No.] ? NO
Instruction 1 : 10 [Box 10] + 10 [Box 10] = 20[Box 10]
Instruction 2 : 10 [Box No.] + 2 = 12 [Box No.]
Instruction 3 : IS 10 [Box 1] < 12 [Box No.] ? YES
ANSWER is 10

Answer: Option A

Assume Box 2 has number 2, Box 3 has number 3 and so on.
And Box 10 has number 4
Instruction 1 : 5 [Box 5] - 5 [Box 5] = 0 [Box 5]
Instruction 2 : 1 [Box 1] + 0 [Box 5] = 1[Box 5]
Instruction 3 : IS 1 [Box No.] < 4 [Box 10] ? YES
Instruction 4 : 1 [Box 5] + 9 [Box 9] = 10 [Box 5]
Instruction 5 : 1 [Box No.] + 1 = 2[Box No.]
Instruction 6 : 9 [Box No.] - 1 = 8 [ Box No.]
Instruction 2 : 2 [Box 2] + 10 [Box 5] = 12 [Box 5]
Instruction 3 : IS 2 [Box No.] < 4 [Box 10] ? YES
Instruction 4 : 12 [Box 5] + 8 [Box 8] = 20 [Box 5]
Instruction 5 : 2 [Box No.] + 1 = 3 [Box No.]
Instruction 6 : 8 [Box No.] - 1 = 7 {box No.]
Instruction 2 : 3 [Box No.] + 20 [Box 5] = 23 [Box 5]
Instruction 3 : IS 3 [Box No.] < 4 [Box 10] ? YES
Instruction 4 : 23 [Box 5] + 7 [Box 7] = 30 [Box 5]
Instruction 5 : 3 [Box No.] + 1 = 4 [Box No.]
Instruction 6 : 7 [Box No.] - 1 = 6 [Box No.]
Instruction 2 : 4 [Box 4] + 30 [Box 5] = 34 [Box 5]
Instruction 3 : IS 4 [Box No.] < 4 [Box 10] ? NO
ANSWER Box 10 = 4