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Study the flow chart give below and the questions that follow
Question: At the end of the flow chart the number placed in which of the following boxes will remain unchanged
ABox 3
BBox 10
CBox 2
DBox 7
Answer: Option D
Explanation:ANSWR d)Box 7
Explanation :
In instruction 1, Box 10 is modified;
In instruciton 3, Box 2 is modified;
and in instruction 5, Box 3 gets mofied;
Therefore out of given options only Box 7 remains unchanged.
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Is the following statement True or False
Statement:
If the condition in Step C updates the value in Box 3 instead of Box 2, then the flow chart will enter into infinite loop
ATRUE
BFALSE
CCannot be determined
Answer: Option B
Explanation:Answer b)FALSE
Explanation.
even if Box 3 is updated instead of Box 2 in instruction C,
In instruction D, Number in Box 2 is compared with Box 7,
and the value is anyway greater, so the result is YES there and thus exiting and finishing the loop.
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Study the flow chart give below and the questions that follow.
The purpose of the following chart is to put a zero in each of the boxes 2,4 and 6. In order to accomplish exactly this - no more and no less - Which number must be in box 3?
A0
B6
C10
D3
E8
Answer: Option D
Explanation:The answer is E.
The instruction 1 gets modified as long as the condition becomes false.
Step 1 defines (on the first occurance) and executes the instruction
Step 2 modifies the instruction
Step 3 does an evaluation
On each loop, the box 2, 4, 6, 8, 10... gets filled with 0. We need to limit it until 6 only.
When the last box count becomes 6, we need to execute the instruction. So, box 3 should not have 6. After executing instruction, it updates the box number to 8. Here, we need to break.
So, box 3 should contain 8.
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Study the flow chart give below and the questions that follow.
What number is now in Box 8?
What number is now in box 11?
A11, 5
B11, 2
C8, 6
D11, 9
Answer: Option D
Explanation:None of the available answers is the correct:
step 1 : ins 1 : 2[Box 11] 3 = 5[Box 11]
step 2 : ins 2 : 8[Box 1] -> 8[Box 10]
step 3 : ins 3 : is 1 an odd number? YES
step 4 : ins 4 : go to instruction 6[Box 2[Box 6]]
step 5 : ins 6 : 4[Box 5] 5[Box 11] = 9[Box 11]
step 6 : ins 7 : change ins2: [Box 1 1] -> [Box 10 - 1]
step 7 : ins 8 : 9 < 8[Box 1] ? NO
step 8 : ins 9 : go to instruction 2
step 9 : ins 2 : 6[Box 2] -> 6[Box 9]
step 10 : ins 3 : is 2 an odd number? NO
step 11 : ins 6 : 4[Box 5] 9[Box 11] = 13[Box 11]
step 12 : ins 7 : change ins2: [Box 2 1] -> [Box 9 - 1]
step 13 : ins 8 : 8 < 8[Box 1] ? NO
step 14 : ins 9 : go to instruction 2
step 15 : ins 2 : 5[Box 3] -> 5[Box 8]
step 16 : ins 3 : is 3 an odd number? YES
step 17 : ins 4 : go to instruction 6[Box 2[Box 6]]
step 18 : ins 6 : 4[Box 5] 13[Box 11] = 17[Box 11]
step 19 : ins 7 : change ins2: [Box 3 1] -> [Box 8 - 1]
step 20 : ins 8 : 7 < 8[Box 1] ? YES
ANSWER: 5[Box 8] and 17[Box 11]
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Study the flow chart give below and the questions that follow.
The purpose of the following chart is to double the number in each of the boxes 2, 4, 6, 8 and 10.
In order to accomplish exactly this - no more and no less - What is the smallest number Which may be in box 1 ?
A19
B15
C9
D11
Answer: Option A
Explanation:Assume [Box 1]= 19
Instruction 1: 2[Box 2] 2[Box 2] = 4[Box 2​]
Instruction 2: [Box 2] 2 = [Box 4] // increase box num from 2 to 4.
Instruction 3: IS [Box 1] 19 < [Box 2] 4 NO
Instruction 1: 4[Box 4] 4[Box 4] = 8[Box 4​]
Instruction 2: [Box 4] 2 = [Box 6]
Instruction 3: IS [Box 1] 19 < [Box 4] 8 NO
Instruction 1: 6[Box 6] 6[Box 6] = 12[Box 6]
Instruction 2: [Box 6] 2 = [Box 8]
Instruction 3: IS [Box 1] 19 < [Box 6]12 NO
Instruction 1: 8[Box 8] 8[Box 8] = 16[Box 8​]
Instruction 2: [Box 8] 2 = [Box 10]
Instruction 3: IS [Box 1] 19 < [Box 8]16 NO
Instruction 1: 10[Box 10] 10[Box 10] = 20[Box 10​]
Instruction 2: [Box 10] 2 = [Box 12]
Instruction 3: IS [Box 1] 19 < [Box 10] 20 YES
END
SO the ans should be 19//option A
// If you put [Box 1] = 9 then instruction end @ Instruction 3: IS [Box 1] 9 < [Box 6]12 Yes
// If you put [Box 1] = 11 then instruction end @ Instruction 3: IS [Box 1] 11 < [Box 6]12 Yes
// If you put [Box 1] = 15 then instruction end @ Instruction 3: IS [Box 1] 15 < [Box 8]16 Yes
As per mention above we have to double 2,4,6,8,10 value...so loop never ends before updating upto
[Box 10] thats why our ans become 19
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Study the flow chart give below and the questions that follow.
A27
B23
C12
D34
Answer: Option A
Explanation:Instruction 1 : 0 [Box 3] + 1 [Box 11] = 1 [Box 11]
Instruction 2 : 1 [Box 1] + 1 [Box 11] = 2 [Box 5]
Instruction 3 : 3 [Box 4] * 3 [Box 4] = 9 [Box 4]
Instruction 4 : IS 2 [Box 5] = 6 [Box 10] ? NO
Instruction 5 : 9 [Box 4] - 6 = 3 [Box 4]
Instruction 6 : 2 [Box 5] + 2 [Box 2] = 4 [Box 5]
Instruction 3 : 3 [Box 4] * 3 [Box 4] = 9 [Box 4]
Instruction 4 : IS 4 [Box 5] = 6 [Box 10] ? NO
Instruction 5 : 9 [Box 4] - 6 = 3 [Box 4]
Instruction 6 : 4 [Box 5] + 2 [Box 2] = 6 [Box 5]
Instruction 3 : 3 [Box 4] * 3 [Box 4] = 9 {box 4]
Instruction 4 : IS 6 [Box 5] = 6 [Box 10] ? YES
Instruction 7 : 24 [Box 7] - 6 [Box 5] = 18 [Box 8]
Instruction 8 : 9 [Box 4] + 18 [Box 8] = 27 [Box 6]
ANSWER Box 6 = 27
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Study the flow chart give below and the questions that follow.
A19
B15
C11
D14
Answer: Option D
Explanation:Instruction 1 : 5 [Box 4] + 2 [Box 10] = 3 [Box 1]
Instruction 2 : 3 [Box 1] + 3 [Box 6] = 6 [Box 1]
Instruction 3 : IS 6 [Box 1] evenly divisible by 4? = NO
Instruction 4 : 6 [Box No.] + 3[Box 6] = 9 [Box No.]
Instruction 5 : IS 13 [Box 2] > 9[Box No.] ? = YES
Instruction 6 : 7[Box 9] - 1 = 6 [Box 9]
Instruction 2 : 6 [Box 1] + 6 [Box 9] = 12 [Box 1]
Instruction 3 : IS 12 [Box 1] evenly divisible by 4? = NO
Instruction 4 : 9[Box No.] + 3[Box 6] = 12[Box No.]
Instruction 5 : IS 13 [Box 2] > 12 [Box No.] ? = YES
Instruction 6 : 6 [Box 9] -1 = 5 [Box 9]
Instruction 2 : 12 [Box 1] + 2 {Box 12] =14[Box 1]
Instruction 3 : IS 14 [Box 1] evenly divisible by 4? = NO
Instruction 4 : 12 [Box No.] + 3 [Box 6] = 15 [Box No.]
Instruction 5 : IS 13 [Box 2] > 15 [Box No.] ? = NO
ANSWER Box 1 = 14
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The purpose of the following flowchart is to add the numbers in boxes 6, 7, 8, and 9 and put the total into box 3.
In order to accomplish exactly this - no more and no less - what number must be in box 4?
A4
B7
C6
D8
Answer: Option B
Explanation:If Box 4 = 7
Instruction 1 : 5[ Box 1] - 5 [Box 1] = 0 [Box 3]
Instruction 2 : 0 [Box 3] + 3 {Box 9] = 3 [Box 3]
Instruction 3 : IS 7[Box 4] > 9[Box No.] ? = NO
Instruction 4 : 9 [Box No.] - 1 = 8 [Box No.]
Instruction 2 : 3 [Box 3] + 7 [Box 8] = 10 [Box 3]
Instruction 3 : IS 7[Box 4] > 8[Box No.] ? = NO
Instruction 4 : 8 [Box No.] - 1 = 7 [Box No.]
Instruction 2 : 10 [Box 3] + 6 [Box 7] = 16 [Box 3]
Instruction 3 : IS 7[Box 4] > 7[Box No.] ? = NO
Instruction 4 : 7 [Box No.] - 1 = 6 [Box No.]
Instruction 2 : 16 [Box 3] + 8 [Box 6] = 24 [Box 3]
Instruction 3 : IS 7[Box 4] > 6[Box No.] ? = YES
ANSWER Box 4 = 7
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The purpose of the following flow chart is to double the number in each of the Boxes 2, 4,6,8 and 10.
In order to accomplish exactly this - no more and no less - What is the smallest number which may be in box 1?
A43
B12
C10
D11
Answer: Option C
Explanation:Assume Box 2 has number 2, Box 3 has number 3 and so on.
And Box 1 has number 10
Instruction 1 : 2 [Box 2] + 2[Box 2] = 4[Box 2]
Instruction 2 : 2 [Box No.] + 2 = 4 [Box No.]
Instruction 3 : IS 10 [Box 1] < 4 [Box No.] ? NO
Instruction 1 : 4 [Box 4] + 4{Box 4] = 8[Box 4]
Instruction 2 : 4 [Box No.] + 2 = 6 [Box No.]
Instruction 3 : IS 10 [Box 1] < 6 [Box No.] ? NO
Instruction 1 : 6 [Box 6] + 6 [Box 2] = 12[Box 6]
Instruction 2 : 6 [Box No.] + 2 = 8 [Box No.]
Instruction 3 : IS 10 [Box 1] < 8 [Box No.] ? NO
Instruction 1 : 8 [Box 8] + 8 [Box 8] = 16[Box 8]
Instruction 2 : 8 [Box No.] + 2 = 10 [Box No.]
Instruction 3 : IS 10 [Box 1] < 10 [Box No.] ? NO
Instruction 1 : 10 [Box 10] + 10 [Box 10] = 20[Box 10]
Instruction 2 : 10 [Box No.] + 2 = 12 [Box No.]
Instruction 3 : IS 10 [Box 1] < 12 [Box No.] ? YES
ANSWER is 10
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Study the flow chart give below and the questions that follow.
A4
B2
C6
D9
E1
Answer: Option A
Explanation:Assume Box 2 has number 2, Box 3 has number 3 and so on.
And Box 10 has number 4
Instruction 1 : 5 [Box 5] - 5 [Box 5] = 0 [Box 5]
Instruction 2 : 1 [Box 1] + 0 [Box 5] = 1[Box 5]
Instruction 3 : IS 1 [Box No.] < 4 [Box 10] ? YES
Instruction 4 : 1 [Box 5] + 9 [Box 9] = 10 [Box 5]
Instruction 5 : 1 [Box No.] + 1 = 2[Box No.]
Instruction 6 : 9 [Box No.] - 1 = 8 [ Box No.]
Instruction 2 : 2 [Box 2] + 10 [Box 5] = 12 [Box 5]
Instruction 3 : IS 2 [Box No.] < 4 [Box 10] ? YES
Instruction 4 : 12 [Box 5] + 8 [Box 8] = 20 [Box 5]
Instruction 5 : 2 [Box No.] + 1 = 3 [Box No.]
Instruction 6 : 8 [Box No.] - 1 = 7 {box No.]
Instruction 2 : 3 [Box No.] + 20 [Box 5] = 23 [Box 5]
Instruction 3 : IS 3 [Box No.] < 4 [Box 10] ? YES
Instruction 4 : 23 [Box 5] + 7 [Box 7] = 30 [Box 5]
Instruction 5 : 3 [Box No.] + 1 = 4 [Box No.]
Instruction 6 : 7 [Box No.] - 1 = 6 [Box No.]
Instruction 2 : 4 [Box 4] + 30 [Box 5] = 34 [Box 5]
Instruction 3 : IS 4 [Box No.] < 4 [Box 10] ? NO
ANSWER Box 10 = 4
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