# Infosys Placement Questions & Answers :: Infosys

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## Total Qs: 284+

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Choose the correct option.

How many numbers are divisible by 4 between 1 to 100 ?

A25

B24

C18

D20

| | Important Formulas | Topic: | Asked In Infosys |

Explanation:

Here is no explanation for this answer

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A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?

A32 years

B46 years

C40 years

D44 years

| | Important Formulas | Topic: | Asked In Infosys |

Explanation:

Lets assume mother's present age = x years
So, the person's present age = 2/5 x years
As per the question:
=>(2/5 x + 8) = 1/2 (x + 8)
=> 2(2x + 40) = 5(x + 8)
=> x = 40
So Mother present age = 40 years.

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In how much time would the simple interest on a certain sum be 0.125 times the principal at 10% per annum?

A2 3/4 years

B1 1/4 years

C2 1/4 years.

D3 1/4 years.

| | Important Formulas | Topic: | Asked In InfosysHireMee |

Explanation:

Lets assume sum = x.
Then, S.I. = 0.125x = 1/8 *x, GivenR = 10%
Formula: Time = (100 * S.I)/(P * R)
Time = (100 *1/8* x) / (x * 10) = (100 *x)/(x*8*10)
= 5/4 = 1 1/4 years.

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A pupil's marks were wrongly entered as 83 instead of 63. Due to the average marks for the class got increased by half. The number of pupils in the class is:

A40

B73

C12

D23

| | Important Formulas | Topic: | Asked In Infosys |

Explanation:

Lets assume total pupils in the class = x
As per the question: increased by 1/2.
Total increase in marks = (x * 1/2) = x/2
=> x/2 = (83 - 63)
=> x/2 = 20
=> x = 40

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If Rs 510 be divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/4 of what C gets, then their shares are respectively:

ARs 65, Rs 90, Rs 360

BRs 150, Rs 300, Rs 60

CRs 60, Rs 90, Rs 300

DRs 60, Rs 90, Rs 360

| | Important Formulas | Topic: | Asked In Infosys |

Explanation:

A per the question:
A = 2/3 B and B = 1/4 C
=> A/B = 2/3 and B/C = 1/4
Or A:B = 2:3 and B:C = 1:4 = 3:12
=> A:B:C = 2:3:12
So, A's share = 510 * 2/17 = Rs 60
B's share = 510 * 3/17 = Rs 90
C's share = 510 * 12/17 = Rs 360.

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There is 60% increase in an amount in 6 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate?

ARs. 3420

BRs. 3120

CRs. 3972

DRs. 3240

| | Important Formulas | Topic: | Asked In Infosys |

Explanation:

Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.
R = (100 x 60)/(100x6) = 10% p.a.
Now, P = Rs. 12000
T = 3 years and R = 10% p.a.
So, C.I. = Rs.[12000 * [(1 + 10/100)^3- 1]]
= Rs. 12000 * 331/1000 = Rs. 3972

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In an election between two candidates first candidate got 60% of votes polled and second Candidate got 280 votes. The total number of votes polled was?

| | Important Formulas | Topic: | Asked In Infosys |

Explanation:

Let's assume total polled votes = 100 %,
Given, First person got 60%
than 40 % = 280
40% = 40*7 = 280

100% = 100*7 = 700 votes

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Two vessels A and B contain spirit and water mixed in the ratio 5:2 and 7:6 respectively. Find the ratio in which these mixture be mixed to obtain a new mixture in vessel c containing spirit and water in the ratio 8:5?

A7:9

B9:7

C3:8

D8:9

Explanation:

Let's assume C.P. of spirit = Re. 1 per litre.
Spirit in 1 litre mix. of A = 5/7 litre. So C.P of 1 litre mix in A = Re. 5/7.
Spirit in 1 litre mix. of B = 7/13 litre. So C.P of 1 litre mix in B = Re. 7/13.
Spirit in 1-litre mix. of C = 8/13 litre. So C.P. of 1 litre mix in C = Re. 8/13.
By rule of an allegation, we have required ratio X:Y.

(5/7) (7/13)
\ /
(8/13)
/ \
(1/13) (9/91)

So, required ratio = 1/13 : 9/91 = 7:9.

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On the two sides of a road are two tall buildings exactly opposite to each other. The height of the taller building is 60 m. If the angle of elevation from the top of the smaller building to the top of the taller one is 30Â° and the angle of depression from top of the taller building to the foot of the smaller one is 30Â°, then find the height of the smaller building.

A45 m.

B30 m.

C40 m.

D20 m.

| | Important Formulas | Topic: | Asked In Infosys |

Explanation:

Let AB be the taller building of height 60m and CD be the smaller one of height h m.

tan30= DB/AB = DB/60 = 1/v3

DB = 34.64 m

tan30= AE/CE = AE/DB = 1/v3 = AE/34.64

AE = 60 - h = 20

h = 40 m

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The H.C.F of two numbers is 11 and their L.C.M is 7700. If one of the numbers is 275, then the other is:

A308

B208

C318

D283

| | Important Formulas | Topic: | Asked In InfosysGlobal Edge |

Explanation:

Here is no explanation for this answer

ShortCut By :: r

lcm*hcf = product of 2 nos

11*7700=275*?

ans =308