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Practice Tech Mahindra Essay Topics

# Practice Questions & Answers :: HireMee

4.14K

## Total Practice Qs: 239+

NA
SHSTTON
87
Solv. Corr.
35
Solv. In. Corr.
122
Attempted
1 M:57 S
Avg. Time

61 / 239

Choose the correct option.

How many 4-letter words with or without meaning, can be formed out of the letters of the word, 'LOGARITHMS', if repetition of letters is not allowed?

A40

B400

C5040

D2520

| | Important Formulas | Topic: | Asked In CapgeminiHireMee |

Explanation:

LOGARITHMS' contains 10 different letters.

Required number of words = Number of arrangements of 10 letters, taking 4 at a time.
= 10P4
= (10 x 9 x 8 x 7)
= 5040.

Tags: Capgemini

NA
SHSTTON
51
Solv. Corr.
72
Solv. In. Corr.
123
Attempted
0 M:44 S
Avg. Time

62 / 239

Choose the correct option.

Six friends go to pizza corner there are 2 types of pizzas. And six different flavors are there they have to select 2 flavors from 6 flavors. In how many ways we can select?

A6C2

B6P2

C(6C2)/2!

DNone of these

| | Important Formulas | Topic: | Asked In TCSTCS NQTHireMee |

Explanation:

Here is no explanation for this answer

Tags: TCS TCS NQT

NA
SHSTTON
58
Solv. Corr.
98
Solv. In. Corr.
156
Attempted
1 M:55 S
Avg. Time

63 / 239

Choose the correct option.

From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee. In how many ways can it be done?

A564

B645

C735

D756

| | Important Formulas | Topic: | Asked In NagarroHireMee |

Explanation:

We may have (3 men and 2 women) or (4 men and 1 woman) or (5 men only).

Required number of ways = (7C3 * 6C2)+(7C4 * 6C1)+(7C5)
=>[(7*6*5)/(3*2*1) * (6*5)/(2*1)]+(7C3 * 6C1) + (7C2)

=> 525 + [(7*6*5)/(3*2*1)* 6]+[(7*6)/(2*1)]

= (525 + 210 + 21)
= 756

Tags: Nagarro

NA
SHSTTON
44
Solv. Corr.
48
Solv. In. Corr.
92
Attempted
1 M:29 S
Avg. Time

64 / 239

Choose the correct option.

In how many ways can an animal trainer arrange 5 lions and 4 tigers in a row so that no two lions are together

A2880

B1440

C5760

DNone of these

| | Important Formulas | Topic: | Asked In CapgeminiHireMee |

Explanation:

The lions and the tigers can be arranged in 5!*4!= 2880 ways

Tags: Capgemini

NA
SHSTTON
65
Solv. Corr.
13
Solv. In. Corr.
78
Attempted
0 M:39 S
Avg. Time

65 / 239

Choose the correct option.

How many different words can be formed using the letters of the word AMPLITUDE?

A9!

B9C6

C9P6

D9

| | Important Formulas | Topic: | Asked In CapgeminiHireMee |

Explanation:

Here is no explanation for this answer

ShortCut By :: Vikash

AMPLITUDE:

All 9 letters are different so Number of words possible are 9!

Tags: Capgemini

NA
SHSTTON
13
Solv. Corr.
45
Solv. In. Corr.
58
Attempted
0 M:56 S
Avg. Time

66 / 239

Choose the correct option.

There are 6561 balls out of them 1 is heavy. Find the min. no. of times the balls have to be weighed for finding out the heavy ball.

A12

B8

C18

D6

| | Important Formulas | Topic: | Asked In InfosysHireMee |

Explanation:

Here is no explanation for this answer

Tags: Infosys

NA
SHSTTON
6
Solv. Corr.
32
Solv. In. Corr.
38
Attempted
0 M:0 S
Avg. Time

67 / 239

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When 3 dice are simultaneously thrown, which of the following would be obtained?

AResult 1: A 5, a 3 and a 6

BResult 2: A 5 three times

CResult 3: A 5 twice and a 3

DAll three results are equally likely.

| | Important Formulas | Topic: | Asked In Mu-SigmaHireMee |

Explanation:

Here is no explanation for this answer

Tags: Mu-Sigma

NA
SHSTTON
8
Solv. Corr.
16
Solv. In. Corr.
24
Attempted
0 M:0 S
Avg. Time

68 / 239

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8 chairs are numbered from 1 to 8. Two women first choose two chairs from those marked 1 to 4 and 3 men selects 3 chairs from the remaining. Find the number of possible arrangements

A124

B120

C1440

DNone of these

| | Important Formulas | Topic: | Asked In IBMHireMee |

Explanation:

2 women choose 2 chairs from 4 in 4P2 ways.
reamining 6, 3 men selects 3 chairs in 6p3 ways

So, Total arrangements=12*120=1440

Tags: IBM

NA
SHSTTON
6
Solv. Corr.
21
Solv. In. Corr.
27
Attempted
0 M:0 S
Avg. Time

69 / 239

Choose the correct option.

How many 5 digit numbers can be formed which are divisible by 3 using the numerals 0, 1, 2, 3, 4, 5 (WITHOUT REPETITION)

A216

B315

C240

D600

| | Important Formulas | Topic: | Asked In WiproHireMee |

Explanation:

As per the question the five digit number should be divisible by 3.
So, only possible 5 digit numbers are{1,2,3,4,5} => sum is 15 and {0,1,2,4,5} sum=>12
{1, 2, 3, 4, 5} --> 5! =120
and for {0,1,2,4,5}
"0" can not be used at first place as number will be 4 digit.
So,Total numer = (5!-4!) = 96
120+96=216

Tags: Wipro

NA
SHSTTON
11
Solv. Corr.
19
Solv. In. Corr.
30
Attempted
0 M:0 S
Avg. Time

70 / 239

Choose the correct option.

For the word SURITI, if you arrange the letters in dictionary order then what is its rank?

A234

B235

C236

D237

| | Important Formulas | Topic: | Asked In WiproHireMee |

Explanation:

I= 5! =120
R=5!/2 =60
SI=4! =24
SR=4!/2= 12
ST=4!/2= 12
SUI=3! = 6
= 234 WORDS

and the below 2 words as
SURIIT
SURITI
234 + 2 = 236
So, rank = 236