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51 / 239

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Ram invests two sum of money A and B at 10% p.a. and 20% p.a respectively at CI for 2 years. IF the total interest on both the sum is Rs 5350 then find the sum invested in A if the total sum of A and B was Rs 20,000?


ARs 5000

BRs 10000

CRs 12000

DRs 15000

ENone of these

Answer: Option D

Explanation:

At 10% CI in 2 years=21 %
At 20% Ci in 2 years =44%
and 5350 is 107/4% of 20000, by using allegation
A B
21 44
107/4
3 1
A=3/4*20000= Rs 15000

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52 / 239

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A sum of Rs 343 becomes 512 in 3 years at C.I. Find the rate of interest.
A


A14 (2/7) %

B12.5 %

C8 (2/3) %

D16 (2/3) %

ENone of these

Answer: Option A

Explanation:

Sum=353; Amount=512
as many year, put that many root i.e
cuberoot(343): cuberoot(512)
7:8
rate=(8-7)/7 *100 =14 (2/7)%

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53 / 239

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If the ratio of difference between CI and SI for 3 years and 2 years is 31:10, then find the Rate of Interest.


A11.11%

B10%

C20%

D25%

ENone of these

Answer: Option B

Explanation:

Sum= A
Interest= B
A——–A———A
———-B———B
———————B
———————C
CI for 3 years=3A+3B+C
SI for 3 years =3A
Diff= 3B+cCI for 2 years=2A+B
SI for 2 years=2A
diff=B
ratio=(3B+C)/B=31/10
B=10; C=1
Rate=C/B=1/10=10%

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54 / 239

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A sum of Rs 6,000 was taken as a loan. This is to be repaid in two equal annual installments. If the rate of interest is 20% compounded annually then find the value of each installment.


ARs 4400

BRs 2220

CRs 4320

DRs 4420

ENone of these

Answer: Option C

Explanation:

Formula= x/(1+R/100)^T
x/ (1+20/100)^1 + x/(1+20/100)^2 = 6600
solve and get x=4320

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55 / 239

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A sum of money amounts to Rs.6690 after 3 years and to Rs.10035 after 6 years on compound interest. Find the sum.


ARs.4400

BRs.4560

CRs.4600

DRs.4460

Answer: Option D

Explanation:

Let's assume the Sum = Rs. P.
P [1 + (R/100)]^3 = 6690 -------- (i)
P [1 + (R/100)]^6 = 10035 ----------(ii)
On dividing, we get [1 + (R/100)]^3 = 10035/6690 = 3/2.
P * (3/2) = 6690 or P = 4460.
Hence, the sum is Rs. 4460.

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56 / 239

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The difference between simple interest and compound interest on a certain deposit for two years at 8 p.c.p. is Rs. 8. What is the amount of deposit


ARs. 2250

BRs. 1250

CRs. 1550

DRs. 2000

ENone of these

Answer: Option B

Explanation:

Given Intrest rate r = 8%
Deposited for year n = 2 years
Formula: SI = p*n*r/100
=> p*2*8/100 = 4p/25
CI = Amount - p
Amount = p(1 + r/100)^n
=> p(1 + 8/100)^2
CI = p(27/25)^2 - p
p(27/25)^2- p - 4p/25 = 8
p[27*27 - 625 - 100]/625 = 8
4p = 5000 => p = Rs. 1250

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A sum of money triples itself at compound interest in 3 years. In 9 years it will be


A6 times the principal

B12 times the principal

C18 times the prinipal

D27 times the principal

Answer: Option D

Explanation:

p(1+ r/100) ^n=ci
p(1+r/100) ^ 3=3p
(1+r/100) ^3=3 , p(1+r/100) ^9=p(3)^3 = 27 times

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58 / 239

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If you deposit Rs. 110 in a bank at a simple interest of 12% per year, how much money will you have in the bank after 2 years?


A134

B136.4

C26.4

D24

E136

Answer: Option B

Explanation:

SI=PTR/100
SI=(110*2*12)/100
SI=26.4
Total amount aftr 2 yrs=P+SI=110+26.4=136.4

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59 / 239

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At a certain rate of simple interesrt,a sum double itsef in 10 years.In how many years would it treble itsef?


A30

B40

C15

DData inadequate

ENone of these

Answer: Option E

Explanation:

Lets Assume after 10 years amount = 2p
so, SI=2P-P = P
P=(P*R*10)/100
r=10%
now amount = 3P
SI= 3P-P=2P
2P=(P*10*T)/100
T=20years

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60 / 239

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If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, what is the compound interest on the same at the same rate and for the same time?


ARs. 51.25

BRs. 54.25

CRs. 60

DRs. 52

Answer: Option A

Explanation:

Sum = Rs. (50 * 100)/(5*2) = Rs. 500.

Amount = Rs. [500 * (1 + 5/100)2]

= Rs. (500 * 21/20 * 21/20 )
= Rs. 551.25

C.I. = Rs. (551.25 - 500) = Rs. 51.25

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