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Choose the correct option.

HCF of \(2^2 \times 3^2 \times 7^2\) and \( 2 \times 3^4 \times 7\) is?


A128

B126

C146

D434

Answer: Option B

Explanation:

we need to get the common highest factors among given values.
So we got
2

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If (x - 4) is the HCF of \( x^2 - 8x + 15 \) and \(x^2 - kx +1\) , then what is k?


A15-Aug

B4

C5

D15/8

Answer: Option B

Explanation:

(x – 4) is HCF i.e. a factor of both equations

The equations must get satisfied for x - 4

Also, when x = 4, both equations are equal in value.

Putting x = 4 in both equations

42 - 8 (4) + 15 = 42 - k(4) + 1

31 – 32 = 17 – 4k

k = 4

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13 / 239

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The L.C.M. Of 2, 2.7 and 0.09 is:


A5.4

B0.54

C5.5

D0.054

Answer: Option D

Explanation:

Given numbers are 2.00, 2.70 and 0.09.

L.C.M. of 2.00, 2.70 and 0.09 is 0.054.

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HCF of three numbers is 12. If they are in the ratio 1:2:3, then the numbers are -


A12, 24, 36

B10,20,30

C5,10,15

D4,8,12

E15, 30, 45

Answer: Option A

Explanation:

Let the numbers be a, 2a and 3a.
Then, their HCF = a so a=12
The numbers are 12,24,36

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Find the largest number of four digits which is exactly divisible by 27,18,12,15.


A9700

B9710

C9720

D9730

E9740

Answer: Option C

Explanation:

LCM of 27, 18, 12, 15 is 540.

After dividing 9999 by 540 we get 279 remainder.

So answer will be 9999-279 = 9720

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Let 13 and 273 are the HCF and LCM of two numbers respectively, and if one of them is less than 140 and greater than 60 then what will be that number?


A121

B91

C75

D131

Answer: Option B

Explanation:

Here is no explanation for this answer

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Sum of squares of two numbers is 2754, their HCF is 9, LCM is 135, Find the numbers


A45 and 36

B45 and 27

C54 and 27

DNone of these

 View Answer |  Submit Your Solution | Important Formulas | Topic: H.C.F and L.C.M | Asked In WiproGlobal EdgeHireMee |

Answer: Option B

Explanation:

Product of two no. = H.C.F*L.C.M
So,x*y=135*9=1215 -----(1)
and x^2+y^2=2754
So,(x+y)^2=x^2+y^2+2*x*y = 2754+2*1215=5184
So,x+y=72 ----------- (2)
By solving eq. (1) & (2)
nos. are 45 and 27

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The ratio of two numbers is 3:4 and their HCF is 4.Their LCM is:


A12

B16

C24

D48

Answer: Option D

Explanation:

Given Two No, ratio = 3:4 and their HCF = 4
So, No. = 3*4 =12 and 4*4=16
LCM of 12,16 = 48

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HCF of 2472,1284 and a third number 'n'is 12.If their LCM is 8*9*5*103*107.then the number 'n'is..


A2^2*3^2*5^1

B2^2*3^2*7^1

C2^2*3^2*8103

DNone of these

Answer: Option A

Explanation:

2472 = 2^3×3×103
1284 = 2^2×3×107
HCF = 2^2×3
LCM = 2^3×3^2×5×103×107
HCF of the numbers is the highest number which divides all the numbers. So N should be a multiple of 2^2×3
LCM is the largest number that is divided by the given numbers. As LCM contains 32×5 these two are from N.
So N = 2^2×3^2×5^1

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The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:


A1677

B1683

C1898

D3363

ENone of these

Answer: Option B

Explanation:

L.C.M. of 5, 6, 7, 8 = 840.

Required number is of the form 840k + 3

Least value of k for which (840k + 3) is divisible by 9 is k = 2.

Required number = (840 * 2 + 3) = 1683.

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