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Choose the correct option.

9.99 x 9.9 x 9


A2.76

B2.99

C3.1

D3.33

Answer: Option D

Explanation:

\(= \frac{(9.99 \times 9.9 \times 9)}{(9.9 \times 0.9 \times 0.3)} = 3.33\)

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Choose the correct option.

\(12^{4.5} \times 12^? = 12^{5.6} \times 12^{1.8}\)


A1.5

B1.8

C2.9

D3.1

Answer: Option C

Explanation:

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Choose the correct option.

789.009 - ? + 56.84 = 215.943


A899.015

B752.804

C714.642

D629.906

Answer: Option D

Explanation:

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Arrange the fractions in ascending order


A5/8 < 7/12 < 3/4< 13/16

B5/8 < 7/12 < 13/16 < 3/4

C5/8 < 3/4< 13/16 < 7/12

D7/12 < 5/8 < 3/4< 13/16

Answer: Option D

Explanation:

5/8 = .625, 7/12 = .5833, 3/4 = .75, 13/16 = .8125

So order will be
7/12 < 5/8 < 3/4< 13/16

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What decimal of an hour is a second


A0.0028

B0.0027

C0.0026

D0.0025

E0.0024

Answer: Option B

Explanation:

1/(60*60) = 1/3600 = .0027

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If 144/0.144 = 14.4/x, then x = ?


A0.144

B0.0144

C0.00144

D0.000144

E1.44

Answer: Option B

Explanation:

1000 =14.4/x

x=14.4/1000

= 0.0144

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Evaluate: (2.39pow2−1.61pow2) / (2.39−1.61)


A2

B3

C4

D5

E6

Answer: Option C

Explanation:

\(\frac{a^2-b^2}{a-b}=4 \)

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What will be vulgar fraction of 0.0056


A7/1150

B7/1175

C7/1250

D7/1275

Answer: Option C

Explanation:

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Water is continuously poured from a reservoir to a locality at the steady rate of 10,000 liters per hour. When delivery exceeds demand, the excess water is stored in a tank. If the demand for 8 consecutive three-hour periods is 10000,10000,45000,25000,40000,15000,60000 and 35000 liters respectively, what will be the minimum capacity required of the water tank (in 1000 litres) to meet the demand?


A10

B30

C40

D50

 View Answer |  Submit Your Solution | Important Formulas | Topic: Alligation or Mixture | Asked In HCL TechnologiesSSC CGL Tier I |

Answer: Option C

Explanation:

In the period of First 3 hrs, the demand of water = 10000.
but the water poured by 10000 per hour.
Thus the end of 3 hours it will poured 30000 ltr then the excess of water = 20000.
Similarly at the end of Second 3 hrs period the excess of water 20000+20000 = 40000.

Third, 3 hrs water poured = 30000
already we have 40000 of excess water and demand 45000.
Then the excess water at the end of 3rd 3 hrs= 40000+30000–45000= 25000
Fourth 3 hrs. water = 25000+30000–25000= 30000
Fifth = 30000+30000–40000= 20000
Sixth = 20000+30000–15000=35000
Seventh = 35000+30000–60000= 5000
Eighth = 5000+30000–35000= 0
By analyzing the above results, we have 40000 ltrs is the highest measure of excess water.
So the minimum capacity of water tank = 40000 litres = 40
i.e. = 40

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Choose the correct option.

81*82*83*84*85*86*87*89. What should be in the unit place in this product?


A0

B1

C2

D3

 View Answer |  Submit Your Solution | Important Formulas | Topic: Simplification | Asked In HCL TechnologiesHireMee |

Answer: Option A

Explanation:

It should be zero in the unit place in this product.
85*82 will give zero in unit place.

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aditya rai8 months ago

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