Practice Questions & Answers :: AMCAT
AMCAT
Tot. Mock Test: 87+
Tot. Exam. Sec.: 4+
Total Practice Qs: 309+
21 / 309
If abc4d is divisible by 4, then d cannot be:
A0
B4
C8
D2
Answer: Option D
Explanation:40,44,48 is divisible by 4.
not 42. hence d cannot be 2
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22 / 309
A and B invest money in the ratio 3:4 and they has loss of Rs.7000 at the end of year. what is the share of loss of B?
ARs.4000
BRs.3000
CRs.7000
DRs.2000
Answer: Option A
Explanation:Share of loss of B = 7000 *4/7 = Rs. 4000
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23 / 309
A jar contains 2 red, 3 blue, and 4 green marbles. Niki draws one marble from the jar, and then Tom draws a marble. What is the probability that Niki will draw a green marble and Tom will draw a blue marble?
A1/6
B2/8
C5/6
D3/8
Answer: Option A
Explanation:P(green, blue) = 4/9 * 3/8 = 1/6
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24 / 309
The base of a triangular field is three times its altitude. If the cost of cultivating the field at Rs. 24.68 per hectare be Rs. 333.18, find its base and height.
ABase = 100 m & Height = 200m.
BBase = 900 m & Height = 300m.
CBase = 1900 m & Height = 300m.
DBase = 900 m & Height = 1300m.
Answer: Option B
Explanation:Area of the field = Total cost/Rate = (333.18/24.68) hectares =13.5 hectares.
= (13.5*10000) m^2 =135000m^2.
Let altitude = x meters and base = 3x meters.
Then, 1/2 *3x* x= 135000 or x^2 = 9000 or x= 300.
Therefore, base =900 m & altitude = 300m.
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25 / 309
(0.1*0.1*0.1 + 0.02*0.02*0.02)/(0.2*0.2*0.2 + 0.04*0.04*0.04) is equal to
A0.125
B0.25
C0.5
D0.855
Answer: Option A
Explanation:Lets assume 0.1 as a so 0.2 will be 2a
and 0.02 as b so 0.04 will be 2b
Simplify the give equation
(a*a*a + b*b*b)/(2a*2a*2a+2b*2b*2b) => (a^3+b^3)/(8*a^3+8*b^3)
=> (a^3+^3)/8(a^c+b^3) = 1/8 = 0.125
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26 / 309
If (a^2 + b^2 + 1/a^2 + 1/b^2) = 4, then the value of (a^2 + b^2) will be
A1
B2
C1 1/2
D2 1/2
Answer: Option B
Explanation:Given (a^2 + b^2 + 1/a^2 + 1/b^2) = 4
Simplify the above eq.
=> a^2 + 1/a^2 +b^2 + 1/b^2 = 4
=> (a-1/a)^2 + 2 + (b - 1/b)^2 + 2 = 4
=> (a-1/a)^2 + (b - 1/b)^2 = 0
=> (a - 1/a) = 0; (b - 1/b) = 0
=> a = b = (+-)1
so (a^2+b^2) = 1+1 = 2
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27 / 309
if (2x + 2/x) = 1, then the value of (x^3 + 1/x^3) is
A13/8
B11/8
C-11/8
D-13/8
Answer: Option C
Explanation:(2x + 2/x) = 1
=> (x + 1/x) = 1/2
(x^3+1/x^3) = (x+1/x)^3-3x*1/x(x+1/x)
= (1/2)^3-1/2 = (1/8 - 3/2) = (1-12)/8= -11/8
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28 / 309
If A:B = 2:3, B:C = 4:5 and C:D = 5:9,then A:D is equal to
A11:17
B8:27
C5:9
D2:9
Answer: Option B
Explanation:A/B*B/C*C/D= 2/3*4/5*5/9
=> A/D = 8/27
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29 / 309
For what values of 'm' is y = 0, if y = x^2 + (2m + 1)x + m^2 - 1? x is a real number.
Am >= -2
Bm < 0
Cm = 0
Dm >= -1.25
Answer: Option D
Explanation:Here is no explanation for this answer
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30 / 309
Rs.432 is divided amongst three workers A, B and C such that 8 times A's share is equal to 12 times B's share which is equal to 6 times C's share. How much did A get?
ARs. 134.
BRs. 140.
CRs. 144.
DRs. 212.
Answer: Option C
Explanation:8 times A's share = 12 times B's share = 6 times C's share.
Note that this is not the same as the ratio of their wages being 8 : 12 : 6
In this case, find out the L.C.M of 8, 12 and 6 and divide the L.C.M by each of the above
numbers to get the ratio of their respective shares.
The L.C.M of 8, 12 and 6 is 24.
Therefore, the ratio A:B:C :: 24/8 : 24/12 : 24/6
=> A : B : C :: 3 : 2 : 4
The sum of the total wages = 3x + 2x + 4x = 432 => 9x = 432 or x = 48.
Hence A gets 3 * 48 = Rs. 144.
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