Practice Questions & Answers :: AMCAT

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Tot. Mock Test: 66+


Tot. Exam. Sec.: 4+


Total Practice Qs: 260+

NA
SHSTTON
25
Solv. Corr.
89
Solv. In. Corr.
114
Attempted
2 M:7 S
Avg. Time

1 / 260

Choose the correct option.

On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is:


ARs. 45

BRs. 50

CRs. 55

DRs. 60

Answer: Option D

Explanation:

(C.P. of 17 balls) - (S.P. of 17 balls) = (C.P. of 5 balls)

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NA
SHSTTON
10
Solv. Corr.
13
Solv. In. Corr.
23
Attempted
0 M:0 S
Avg. Time

2 / 260

Choose the correct option.

The two trains of lengths 400m, 600m respectively, running at same directions. The faster train can Cross the slower train in 180sec, the speed of the slower train is 48km. then find the speed of the Faster train?


A58 Kmph

B78 kmph

C55 Kmph

D68 Kmph

Answer: Option D

Explanation:

Length of the two trains = 600m + 400m = 1000m



Let's Assume Speed of the first train = x kmph

Speed of the second train= 48 Kmph

So Relative Speed = (x - 48) kmph =((x -48) * 5/18) m/sec

1000/((x -48) * 5/18) = 180

18000/(5x - 240) = 180

100 = 5X - 240

=> 5x = 340 => x = 68 kmph

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NA
SHSTTON
8
Solv. Corr.
15
Solv. In. Corr.
23
Attempted
0 M:0 S
Avg. Time

3 / 260

Choose the correct option.

(0.1*0.1*0.1 + 0.02*0.02*0.02)/(0.2*0.2*0.2 + 0.04*0.04*0.04) is equal to


A0.125

B0.25

C0.5

D0.855

Answer: Option A

Explanation:

Lets assume 0.1 as a so 0.2 will be 2a
and 0.02 as b so 0.04 will be 2b
Simplify the give equation
(a*a*a + b*b*b)/(2a*2a*2a+2b*2b*2b) => (a^3+b^3)/(8*a^3+8*b^3)
=> (a^3+^3)/8(a^c+b^3) = 1/8 = 0.125

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NA
SHSTTON
7
Solv. Corr.
14
Solv. In. Corr.
21
Attempted
0 M:1 S
Avg. Time

4 / 260

Choose the correct option.

If (a^2 + b^2 + 1/a^2 + 1/b^2) = 4, then the value of (a^2 + b^2) will be


A1

B2

C1 1/2

D2 1/2

Answer: Option B

Explanation:

Given (a^2 + b^2 + 1/a^2 + 1/b^2) = 4
Simplify the above eq.
=> a^2 + 1/a^2 +b^2 + 1/b^2 = 4
=> (a-1/a)^2 + 2 + (b - 1/b)^2 + 2 = 4
=> (a-1/a)^2 + (b - 1/b)^2 = 0
=> (a - 1/a) = 0; (b - 1/b) = 0
=> a = b = (+-)1
so (a^2+b^2) = 1+1 = 2

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NA
SHSTTON
7
Solv. Corr.
22
Solv. In. Corr.
29
Attempted
0 M:0 S
Avg. Time

5 / 260

Choose the correct option.

if (2x + 2/x) = 1, then the value of (x^3 + 1/x^3) is


A13/8

B11/8

C-11/8

D-13/8

Answer: Option C

Explanation:

(2x + 2/x) = 1
=> (x + 1/x) = 1/2
(x^3+1/x^3) = (x+1/x)^3-3x*1/x(x+1/x)
= (1/2)^3-1/2 = (1/8 - 3/2) = (1-12)/8= -11/8

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Tags: Global Edge

NA
SHSTTON
15
Solv. Corr.
14
Solv. In. Corr.
29
Attempted
0 M:0 S
Avg. Time

6 / 260

Choose the correct option.

If A:B = 2:3, B:C = 4:5 and C:D = 5:9,then A:D is equal to


A11:17

B8:27

C5:9

D2:9

Answer: Option B

Explanation:

A/B*B/C*C/D= 2/3*4/5*5/9
=> A/D = 8/27

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Tags: Global Edge

NA
SHSTTON
1
Solv. Corr.
5
Solv. In. Corr.
6
Attempted
0 M:0 S
Avg. Time

7 / 260

Alice and Bob play the following coins-on-a-stack game. 20 coins are stacked one above the other. One of them is a special (gold) coin and the rest are ordinary coins. The goal is to bring the gold coin to the top by repeatedly moving the topmost coin to another position in the stack.
Alice starts and the players take turns. A turn consists of moving the coin on the top to a position i below the top coin (0 = i = 20). We will call this an i-move (thus a 0-move implies doing nothing). The proviso is that an i-move cannot be repeated; for example once a player makes a 2-move, on subsequent turns neither player can make a 2-move. If the gold coin happens to be on top when it's a player's turn then the player wins the game. Initially, the gold coinis the third coin from the top. Then


AIn order to win, Alice's first move should be a 1-move.

BIn order to win, Alice's first move should be a 0-move.

CIn order to win, Alice's first move can be a 0-move or a 1-move.

DAlice has no winning strategy.

 View Answer |  Submit Your Solution | Topic: Uncategorized| Asked In TCSAMCAT |

Answer: Option D

Explanation:

Here is no explanation for this answer

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NA
SHSTTON
8
Solv. Corr.
10
Solv. In. Corr.
18
Attempted
0 M:0 S
Avg. Time

8 / 260

Choose the correct option.

A scooterist covers a certain distance at 36 kmph. How many meters does he cover in 2 min?


A800 meters.

B1100 meters.

C700 meters.

D1200 meters.

Answer: Option D

Explanation:

Speed = 36 kmph = 36 * 5/18 = 10mps
So, Distance covered in 2 min = (10 * 2 * 60)m = 1200 meters.

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NA
SHSTTON
6
Solv. Corr.
6
Solv. In. Corr.
12
Attempted
0 M:0 S
Avg. Time

9 / 260

Choose the correct option.

For what values of 'm' is y = 0, if y = x^2 + (2m + 1)x + m^2 - 1? x is a real number.


Am >= -2

Bm < 0

Cm = 0

Dm >= -1.25

Answer: Option D

Explanation:

Here is no explanation for this answer

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NA
SHSTTON
6
Solv. Corr.
8
Solv. In. Corr.
14
Attempted
0 M:0 S
Avg. Time

10 / 260

Choose the correct option.

First day of 1999 is sunday what day is the last day


AWednesday

BMonday

CFriday

DSunday

Answer: Option B

Explanation:

Here is no explanation for this answer

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