Placement Questions & Answers :: Infosys

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 A train traveling at 72 kmph crosses a platform in 30 seconds and a man standing on the platform in 18 seconds. What is the length of the platform in meters?

A300 meters.

B550 meters.

C340 meters.

D240 meters.

Answer: Option D

Explanation:

Here is no explanation for this answer

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 A shopkeeper allows a discount of 10% on the marked price and still gains 17% on the whole. Find at what percent above the cost price did he mark his goods.

A35%

B25%

C30%

D45%

Answer: Option C

Explanation:

Lets assume the cost price = Rs. 100.
So SP = 117 (Given gain 17% on the whole.)
Lets assume the marked price = Rs. x
So, 90% of x = 117 (10% discount on marked price)
=> 90/100 * x = 117
=> x = 130
So, shopkeeper marked his goods 30% above the CP.

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 The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?

A16 cm.

B18 cm.

C17 cm.

D19 cm.

Answer: Option B

Explanation:

As per the question:
(Perimeter of rectangle)/Breadth of rectangle) = 5/1
=> 2(l + b)/b = 5/1
=> 2l + 2b = 5b => 3b = 2l =>
b = (2/3)l ----------(1)
Area of rectangle = 216 cm^2
So, l x b = 216
put the value of b from eq. (1).
=> l * (2/3)l = 216 .
l*l = 324 or l^2 = 324
So, l = 18 cm.

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4 / 288

 Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30 degree and 45 degree respectively. If the lighthouse is 100 m high, the distance between the two ships is:

A276 metre

B273 metre

C270 metre

D263 metre

Answer: Option B

Explanation:

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5 / 288

 A merchant has 1000 kg of sugar, part of which he sells at 8% profit and the rest at 18% profit. He gains 14% on the whole. The quantity sold at 18% profit is:

A550 kg.

B400 kg.

C600 kg.

D650 kg.

Answer: Option C

Explanation:

Profit on 1st part Profit on 2nd part:
8% 18%
\ /
Mean Profi 14%
/ \
4 6
Ratio of 1st and 2nd parts = 4 : 6 = 2 : 3
Quantity of 2nd kind = (3/5 ) * 1000 kg = 600 kg

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 Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?

A33, 46

B33, 42

C32, 46

DNone of these

Answer: Option B

Explanation:

Lets assume first student secured x marks.
So second student will secured (x + 9).
Sum of both students marks = x + (x + 9) = (2x + 9)
As per Question, (x + 9) was 56% of the sum of their marks.
So, (x+9) = 56/100(2x+9)
=> (x+9) = 14/25(2x+9)
=> 25x + 225 = 28x + 126
=> x = 33.
So, (x + 9) = 33 + 9 = 42
Hence, their marks are 33 and 42 respectively.

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 If log(base 10) 5 + log(base 10)(5x + 1) = log(base 10)(x + 5) + 1, then x is equal to:

A9

B3

C1

D4

Answer: Option B

Explanation:

Given log(base 10) 5 + log(base 10)(5x + 1) = log(base 10)(x + 5) + 1
=> log(base 10) 5 + log(base 10)(5x + 1) = log(base 10)(x + 5) + log(base 10) 10
Hint: log (base Z)Z = 1
=> log(base 10)[5 (5x + 1)] = log(base 10) [10(x + 5)] ------ (Point to Remember.)
=> 5(5x + 1) = 10(x + 5)
=> 5x + 1 = 2x + 10
=> x = 3

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8 / 288

 From a pack of 52 cards, two cards are drawn together at random. What is the probability of both the cards being kings?

A1/221

B1/212

C1

D25/57

Answer: Option A

Explanation:

Lets assume the sample space = S
Then, n(S) = 52C2 = (52 x 51)/(2x1) = 1326
Let E = event of getting 2 kings out of 4
=> n(E) = 4C2 = (4 x 3)/(2 x 1) = 6
=> P(E) =n(E)/n(S) =6/1326 = 1/221

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9 / 288

 How many three digit numbers abc are formed where at least two of the three digits are same.

A250

B252

C300

D280

Answer: Option B

Explanation:

Total 3 digit numbers = 9 x 10 x 10 = 900
Total number of 3 digit numbers without repetition = 9 x 9 x 8 = 648
So, the number of three digit numbers with at least one digit repeats = 900 - 648 = 252.

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10 / 288

 Find the missing term of the series:-
2,5,10,17,?,41

A38

B41

C28

DNone of these

Answer: Option C

Explanation:

2+3=5, 5+5=10, 10+7=17,
So, the next prime number is 11
so,17+11=28.
and, 28+13=41

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