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41 / 79
What will be the day of the week 15th August, 2010?
ASunday
BMonday
CTuesday
DFriday
Answer: Option A
Explanation:15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 leap years + 7 ordinary years) = (2 * 2 + 7 * 1) = 11 odd days 4 odd days.
Jan. Feb. March April May June July Aug.
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days
227 days = (32 weeks + 3 days) 3 odd days.
Total number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.
Given day is Sunday.
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42 / 79
The angle of elevation of a ladder leaning against a wall is 60 and the foot of the ladder is 4.6 m away from the wall. The length of the ladder is:
A2.3 m
B4.6 m
C7.8 m
D9.2 m
Answer: Option D
Explanation:Here is no explanation for this answer
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43 / 79
The angle of elevation of the sun, when the length of the shadow of a tree _/3 times the height of the tree, is:
A30º
B45º
C60º
D90º
Answer: Option A
Explanation:Here is no explanation for this answer
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44 / 79
Find the odd one out 1, 4, 9, 16, 20, 36, 49
A1
B9
C20
D49
Answer: Option C
Explanation:Here is no explanation for this answer
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45 / 79
A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes ?
A50 meter
B100 meter
C110 meter
DNone of above
Answer: Option B
Explanation:find the relative speed of the thief and policeman = (11-10)km/hr = 1 km/hr
Distance covered in 6 minutes = (1/60)*6=1/10km => 100meters
So distance between them after 6 minutes = (200-100)=100 meters
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46 / 79
An industrial loom weaves 0.128 metres of cloth every second. Approximately, how many seconds will it take for the loom to weave 25 metre of cloth ?
A194 seconds
B195 seconds
C196 seconds
D197 seconds
Answer: Option B
Explanation:Lets assume the time required to weave 25 meters = x sec.
Rule: More cloth means More time (Direct Proportion)
=> 0.128:1::25:x
=>x=[(25*1)/0.128]
=>x=195.31
So time needed ~195 seconds
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47 / 79
There are three numbers, these are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. What will be the sum of three numbers :
A80
B82
C85
D87
Answer: Option C
Explanation:Given that numbers are co primes,
and two products have the middle number in common.
=> Middle number = H.C.F. of 551 and 1073 = 29
so first number is = 551/29 = 19
=> Third number = 1073/29 = 37
Therefore, sum of these numbers is = (19 + 29 + 37) = 85
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48 / 79
When a student weighing 45 kgs left a class, the average weight of the remaining 59 students increased by 200g. What is the average weight of the remaining 59 students
A55
B56
C57
D58
Answer: Option C
Explanation:Lets assume average weight of the 59 students = x kgs.
=> Total weight of the 59 = 59*x
Given when the weight of this student who left is added, the total weight of the class = (59x + 45)
The average weight decreases by 0.2 kgs, when these students included.
=> (59x+45)/60=(x-0.2)
=> (59x+45)= 60(x-0.2)
=> 59x + 45 = (60A - 12)
=> 45 + 12 = 60x - 59x
=> x = 57
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49 / 79
Nirmal and Kapil started a business investing Rs. 9000 and Rs. 12000 respectively. After 6 months, Kapil withdrew half of his investment. If after a year, the total profit was Rs. 4600, what was Kapil's share initially ?
ARs 2300
BRs 2400
CRs 2500
DRs 2200
Answer: Option A
Explanation:Nirmal:Kapil = 9000*12:(12000*6+6000*6) = 1:1
Kapils share = Rs. [4600 *(1/2)) = Rs. 2300
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50 / 79
The size of the dynamic array is deallocated if the array size is less than _________% of the backend physical size.
A20
B30
C40
D10
Answer: Option B
Explanation:The size of the dynamic array is decreased/deallocated if the actual size of the array is less than 30% of the backend physical size. This is used to avoid memory wastage.
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