Click To Get Off-Campus Placement Jobs Info !!!

Accenture Placement Questions & Answers :: Accenture

126.9K

Total Qs: 105+

NA
SHSTTON
27
Solv. Corr.
71
Solv. In. Corr.
98
Attempted
0 M:31 S
Avg. Time

101 / 105

The G.C.D. of 1.08, 0.36 and 0.9 is:

A0.03

B0.9

C0.18

D0.108

Explanation:

Given numbers are 1.08 , 0.36 and 0.90
H.C.F of 108, 36 and 90 is 18 ( G.C.D is nothing but H.C.F)
So H.C.F of given numbers = 0.18

NA
SHSTTON
31
Solv. Corr.
37
Solv. In. Corr.
68
Attempted
0 M:0 S
Avg. Time

102 / 105

Choose the correct option.

In school there are some bicycles and 4 wheeler wagons. One Tuesday there are 58 wheels in the campus. How many bicycles are there?

A2

BBoth C & D

C5

D7

Explanation:

Here is no explanation for this answer

Tags: TCS Accenture

NA
SHSTTON
2
Solv. Corr.
2
Solv. In. Corr.
4
Attempted
0 M:0 S
Avg. Time

103 / 105

Choose the correct option.

If a camera is purchased for Rs 490 and sold for Rs 465.50. Find the loss%

A5%

B11%

C7%

D13%

Explanation:

C.P = Rs 490
S.P = Rs 465.50
Loss = C.P – S.P = 490 – 465.50 = 24.5
Loss% = (loss * 100)/C.P% = 24.5*100/490% = 245/49% = 5%

Tags: Accenture

NA
SHSTTON
30
Solv. Corr.
62
Solv. In. Corr.
92
Attempted
0 M:7 S
Avg. Time

104 / 105

Choose the correct option.

A can do a piece of work in 14 days which B can do in 21 days. They begin together but 3 days before the completion of the work, A leaves off. The total number of days to complete the work is:

A6 3/5

B8 1/2

C10 1/5

D13 1/2

Explanation:

A's 1 day work = $$\frac{1}{14}$$
B' 1 day work = $$\frac{1}{21}$$

A left 3 day before the completion of work.
B's 3 days' work = $$\frac{1}{21} \times 3 = \frac{1}{7}$$
Remaining work = $$1 \times \frac{1}{7} = \frac{6}{7}$$

(A + B)'s 1 day's work = $$\left(\frac{1}{14} + \frac{1}{21}\right) = \frac{5}{42}$$

Now, $$\frac{5}{42}$$ work is done by A and B = 1 day.
or
whole work done by A&B = $$\frac{42}{5}$$
$$\frac{6}{7}$$ part of work done by A and B = $$\frac{42}{5} \times \frac{6}{7} = \frac{36}{5}$$ days.

Hence, total time taken = (3+36/5)days = $$10\frac{1}{5}$$ days.

NA
SHSTTON
260
Solv. Corr.
57
Solv. In. Corr.
317
Attempted
0 M:7 S
Avg. Time

105 / 105

Choose the correct option.

A can do a work in 10 days and B can do the same work in 15 days. So how many days they will take to finish the same work ?

A5 days

B7 days

C9 days

D6 days

Explanation:

First find the 1 day work of both (A & B)
A 1 day's work = 1/10
and
B 1 day's work = 1/15

So (A + B) 1 day's work = (1/10+1/15)
= (3/30+2/30) = 5/30 = 1/6

So Both (A & B) together can finish work in 6 days