# Placement Questions & Answers :: Capgemini

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**Capgemini Practice Q&A**

81. A man reaches his office 30 min late, if he walks from his home at 3 km per hour and reaches 40 min early if he walks 4 km per hour. How far is his office from his house?

**Answer:**** Option B **

**Explanation:**

Lets assume distance between office and his house =x km

Time taken when speed is 3 kmph = x/3 min.

Time taken when speed is 4 kmph = x/4 min.

Difference between time taken 40-(-30) = 70mins = 70/60 hours.

x/3- x/4 = 70/60

x/12= 7/6

x=14 km

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**Tags:** Capgemini

82. A sum of Rs 468.75 was lent out at simple interest and at the end of 1 year and 8 months, the total amount of Rs 500 is received. find the rate of interest.

**Answer:**** Option A **

**Explanation:**

Given principle P=468.75, Rate of Intreset = R%

Total Amount received = Rs 500

=> Total Amount received = Simple Intrest + Principle.

=> 500 = [468.75*(20/12)*R]/100 + 468.75

=> 31.25=156.25*5R/100

=> R=4%

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**Tags:** Capgemini

83. In a certain college, 20% of the boys and 40% of the girls attended the annual college outing. If 35% of all the students are boys, what percent of all the employees went to the outing?

**Answer:**** Option A **

**Explanation:**

Lets assume total students =100

so in that 35 students are boys and remaining 65 will be girl.

20% of boys = (35)*20/100 = 7

40% of girls = (65)*40/100 = 26

Totally (26+7)=33 employee went to outing.

So 33 is 33% in 100

=> 33% employees went for outing.

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**Tags:** Capgemini

84. Radha bought a watch for Rs. 144 and got a percentage of profit equal to the cost price of the watch. What is the cost price of the watch?

**Answer:**** Option B **

**Explanation:**

SP=144

Lets assume cost price of watch= Rs. x

so profit %=x

C.P.= (100/(100+gain%))*S.P. -----(formula to get CP)

x=(100/100+x) *144

=> x^2+100x=14400

=> x^2+180x-80x-14400=0

=> (x+180) (x-80)=0

=> x=-180

=> x=80

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**Tags:** Capgemini

85. Train A starts from Meerut at 12:00 pm & reach at Delhi on 2:30 pm & train B starts from Delhi at 12:15pm and reach at Meerut on 2:15pm. So, when both trains crosses each other ?

**Answer:**** Option C **

**Explanation:**

Lets assume Distance between Meerut & Delhi = x kms

Trains meet t hours after 12.15pm

Speed of A= x/150 kms/min.

speed of B = x/120 kms/min.

Distance covered by A in (t+15) min + Distance covered by B in y hours

=x (x/150)* (y+15) + (x/120) * y = x

=> 1/150 * (y+150) + 1/120 *y = 1

=> y/150 + 1/10 + y/120 = 1

=> Y=60

trains meet at (12.15 + 60) = 1:15 PM

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**Tags:** Capgemini

86. one man can do a piece of work in 10days. one boys join him & he complete the work in 6days . if he gets 50rs for his work then what will be the share of the boy.

**Answer:**** Option B **

**Explanation:**

man can do work in 10 days

man + boy can do a work in =6 days

so work done by man in 1 day is 6

and work done by boy in 1 day is 4.

so share of boy will be (4/10) * 50= 20 Rs.

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**Tags:** Capgemini

87. A square and an equilateral triangle have the same perimeter. What is the ratio of the area of the circle circumscribing the square to the area of the circle inscribed in the triangle?

**Answer:**** Option D **

**Explanation:**

let x be side of square

perimeter of square=4x=perimeter of triangle=3*side of triangle

so side of eq. triangle=(4/3)*x

diameter of circle circumscribing the square=sqrt(2)*x

area of circle circumscribing the square=pi*(sqrt(2)*x)^2/4=(pi/2)*x^2 ----(1)

to find radius of the circle inscribed in the triangle

area of triangle=r*s=sqrt(3)/4 * (4x/3)^2

now s=(4/3)*x+(4/3)*x+(4/3)*x/2=2x

so sqrt(3)/4 * (4x/3)^2=r*2x gives

r={2/3*(3^1/2)}*x

area of the circle inscribed in the triangle=pi*({2/3*(3^1/2)}*x)^2

=pi*(4/27)*x^2 -------(2)

so reqd ratio= eqn(1)/eqn(2)

=((pi/2)*x^2)/(pi*(4/27)*x^2)=27/8

so reqd ratio=27:8

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**Tags:** Capgemini

88. Two trains for Palwal leave Kanpur at 10 a.m and 10:30 am and travel at the speeds of 60 Kmph and 75 Kmph respectively. After how many kilometers from Kanpur will the two trains be together?

**Answer:**** Option B **

**Explanation:**

Lets assume two train meet at X km distance from kanpur.

Given First train speed 60 kmph, second train speed 75 kmph

Second train start after 1/2 hrs.

Time taken by first train to cover X km = x/60 h

Time taken by 2nd train to cover X km=x/75 h

Now, x/60 - x/75=1/2

so x=150.

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**Tags:** Capgemini

89. 5 tables and 10 chairs were sold for 20000.15%gain for table,10%loss on chair.overall profit Rs 750.the CP of table is

**Answer:**** Option A **

**Explanation:**

Lets assume cost of table is X and cost of chair is Y.

sold price is 20000 and profit is 750 .

so cost for both is 19250.

=> 5X+10Y=19250 ------------ (1)

=> 5*(115/100)X + 10* (90/100)Y =20000 ------- (2)

By solving both eq.

We get X=2140

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**Tags:** Capgemini

90. An elephant fell into a wall of depth 20mts.Everyday it climbs 4mts but at the end falls by 2mts.Find the number of days it would take for the elephant to get out of the wall

**Answer:**** Option C **

**Explanation:**

Here is no explanation for this answer

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Here is the list of questions asked in Capgemini Aptitude Test Question with Answers Capgemini Mock Test page 9. Practice Capgemini Written Test Papers with Solutions and take Q4Interview Capgemini Online Test Questions to crack Capgemini written round test. Overall the level of the Capgemini Online Assessment Test is moderate. Only those candidates who clear the written exam will qualify for the next round, so practic all the questions here and take all the free tests before going for final selection process of Capgemini