# Placement Questions & Answers :: Wipro

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1. A' and 'B' complete a work togather in 8 days.If 'A' alone can do it in 12 days.Then how many day 'B' will take to complete the work?

**Answer:**** Option B **

**Explanation:**

A & B one day work = 1/8

A alone one day work = 1/12

B alone one day work = (1/8 - 1/12) = ( 3/24 - 2/24)

=> B one day work = 1/24

so B can complete the work in 24 days.

**ShortCut By ::**

**Aradhya**

A = 12, A+B = 8, B = ?

Take LCM of A & A+B = 24.

So, A=12*2 = 24, A+B = 8*3 = 24, B = 1*24 = 24.

Answer: B = 24days.

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2. Ravi's salary was reduced by 25%.Percentage increase to be effected to bring the salary to the original level is

**Answer:**** Option A **

**Explanation:**

Method: 1

Let's assume Ravi salary = 100

It get reduced by 25% => Salary = 75

75(1 + P/100) = 100

1+ P/100 = 4/3

P = 100/3 = 33 1/3%.

Method: 2

You can use directly formula i.e

[(R*100)/(100-R)]% Where 'R' is decresed %

so put 25 at place of 'R'

=> [(25 * 100)/(100 - 25)]% => [(25 *100)/75]%

=>100/3% = 33 1/3%

**ShortCut By ::**

**ongolu Ashok Kumar**

**by using formula =(r*100)/(100-r)=(25*100)/(100-25)%**

** =2500/75**

=33 1/3%

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3. A and B can finish a piece of work in 20 days .B and C in 30 days and C and A in 40 days. In how many days will A alone finish the job

**Answer:**** Option A **

**Explanation:**

Find one day work for all three

(A+B)'s 1 day work = 1/20 ----(1)

(B+C)'s 1 day work = 1/30 ----(2)

and (C+A)'s 1 day work = 1/40 ----(3)

2(A+B+C) 1 day work = (1/20 + 1/30 + 1/40)

=> (A+B+C) = (6+4+3)/2*120

=> (A+B+C) = 13/240 -----------(4)

By eq. (2) and (4)

A + 1/30 = 13/240

=> A = 13/240 - 1/30 = (13-8)/240 = 1/48

then A's 1 day work = 1/48

so A alon can finish the job = 48 days

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4. Two trains each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is

**Answer:**** Option B **

**Explanation:**

speed of the faster train = 2x m/sec.

Relative speed of train = (x + 2x) m/sec = 3x m/sec.

Total distance = (100 + 100)m = 200m

3x = 200/8

=> 24x = 200 => x = 25/3

So speed of the faster train = 2 * 25/3 m/sec

= 50/3 m/sec

= 50/3 * 18/5 = 60 km/hr.

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5. What is the product of the irrational roots of the equation (2x-1)(2x-3)(2x-5)(2x-7)=9?

**Answer:**** Option A **

**Explanation:**

Here is no explanation for this answer

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6. The total population of a village is 5000. The number of males and females increases by 10% and 15% respectively and consequently the population of the village becomes 5600. what was the number of males in the village ?

**Answer:**** Option B **

**Explanation:**

Lets Assume males and females as x and y respectively.

So total Population (x+y)=5000 -----------(1)

Incresed by 10% and 15%

so (x+(10x/100))+(y+15y/100)=5600

=> 110x/100+115y/100=5600

By Solving eq. (1) & (2)

y=2000 x=3000 (i.e Male population)

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7. A thief steals a car at 2.30 p.m and drives it at 60 kmph. The theft is discovered at 3 p.m and the owner sets off in another car at 75 kmph. When will be overtake the thief.

**Answer:**** Option D **

**Explanation:**

As Theft is discovered at 3:00pm but Thief stole the car at 2:30.

This means thief covered some distance in this 30 min gap.

Distance travelled by thief in 30 min = 60 * 1/2 = 30 km

Owner Discovered Car at 3:00pm

Now relative speed = (75-60)km/hr = 15km/hr

Time needed to travel 30km by the speed of 15km/hr.

Time at which owner meets thief = 30/15 = 2 hrs

So After 2 hrs (i.e,at 5:00 pm) the owner will catch/overtake the thief

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8. Fresh fruit contains 68% water and dry fruit contains 20% water. How much dry fruit can be obtained from 100 kg

**Answer:**** Option C **

**Explanation:**

1. Given fresh fruit has 68% water,

=> Remaining 32% will be fruit content.

2. Given Dry fruit has 20% water

=> Remaining 80% is fruit content.

Here assume weight of dry fruit = x kg.

"fruit content in both the fresh fruit and dry fruit is the same"

Fruit % in fresh-fruit = fruit% in dry-fruit

so (32/100) * 100 = (80/100 )* x

=> x = 40 kg.

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9. A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 9 hours. If both taps are opened simultaneously, then after how much time will the cistern get filled ?

**Answer:**** Option C **

**Explanation:**

Time taken by tap A to fill the cistern=4 hrs

so work done by tap A in 1 hour = 1/4th

Time taken by tap B to empty the full cistern = 9 hours

so work done by tap B in 1 hour = 1/9th

=> Work done by (A + B) in 1 hour=(1/4 - 1/9)=5/36

Therefore, the tank will fill the cistern = 36/5 hours=7.2 hours.

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10. Ronald and Elan are working on an assignment. Ronald takes 6 hours to type 32 pages on a computer, while Elan takes 5 hours to type 40 pages. How much time will they take, working together on two different computers to type an assignment of 110 pages ?

**Answer:**** Option B **

**Explanation:**

Number of pages typed by ronald in 1 hour = 32/6 = 16/3.

Number of pages typed by elan in 1 hour = 40/5 = 8.

Number of pages typed by both in 1 hour = (16/3+8) = 40/3.

Time taken by both to type 110 pages = (110*3/40)hrs = 8 1/4hrs = 8 hrs 15 min.

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