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Placement Questions & Answers :: Cisco

Company: Cisco

Total Qs: 118+

Website: http://www.cisco.com

Total View: 26.55K

Not Attempted

81. func()
{
int x=1;
if(x=1)
x=1000;
else
x=10;
return x;
}
What is the return value?

Answer: Option C

Explanation:

Here is no explanation for this answer

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Not Attempted

82. Find the output for the following C program

#include
int main()
{
int i=20,j,k=0;
for(j=1;j >i;j++)
{
k+=j<10?4:3;

}
printf("%d", k);
}

Answer: Option B

Explanation:

Here is no explanation for this answer

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Not Attempted

83. Find the output for the following C program

#include
int i = 10;
int main()
{
int i =20,n;
for(n=0;n<=i;)
{
int i=10;
i++;
}
printf("%d k", i);
}

Answer: Option C

Explanation:

Here is no explanation for this answer

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Answer: Option A

Explanation:

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Answer: Option B

Explanation:

Here is no explanation for this answer

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 View Answer |  Submit Your Solution | Topic: Unknown| Asked In |

Answer: Option B

Explanation:

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 View Answer |  Submit Your Solution | Topic: Unknown| Asked In |

Answer: Option B

Explanation:

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Not Attempted

88. Four concentric circles are given .The radius of 1st circle is x.next is 2x,then 3x and 4x. Given that area between 2nd and 1st is A and 4th and 3rd circles being B. Find ratio of A to B

Answer: Option A

Explanation:

Area of first circle = pi*(x)^2 = pi*x^2
Area of second circle = pi*(2x)^2 = 4*pi*x^2
Area of third circle = pi*(3x)^2 = 9*pi*x^2
Area of fourth circle = pi*(4x)^2 = 16*pi*x^2
Area b/w 1st and 2nd circles = 3*pi*x^2
Area b/w 3rd and 4th circles = 7*pi*x^2
So, Ratio = 3:7

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Not Attempted

89. A triangle ABC is given, a line DE is parallel to base side and that cuts the triangle. The ratio of area of triangle to the area of trapezium.
Given DE/BC = 3/5.

Answer: Option A

Explanation:

The line DE divides the triangle ABC into 2 parts - triangle ADE and trapezium DBCE.The question is to find the ratio of area(ADE) to area(DBCE).

Now triangle ADE is similar to triangle ABC.
=> DE/BC = AD/AB = AE/AC ....(1)
Drawing a perpendicular from A to BC meeting BC at G and meeting DE at F.
Now AF and AG are the heights of the triangles ADE and ABC resp.
tri(ADF)~tri(ABG) => AD/AB = AF/AG ....(2)
Area of a triangle = 1/2(base*height).
Area of tri(ADE) = 1/2(DE*AF)
Area of tri(ABC) = 1/2(BC*AG)
Area of trapezium(DBCE) = area(ABC)-area(ADE) = 1/2(BC*AG-DE*AF)
Ratio - area(ADE)/area(DBCE) = (DE*AF)/(BC*AG-DE*AF) = 1/[(BC*AG-DE*AF)/(DE*AF)]
(rearranging) = 1/[(BC/DE)*(AG/AF)-1]
Using (1) and (2),(BC/DE)*(AG/AF) = (BC/DE)^2
(using given DE/BC=3/5) => BC/DE=5/3 => (BC/DE)^2 = 25/9
The required ratio = 1/(25/9-1) =1/(16/9) = 9/16

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Not Attempted

90. A company contracts to paint 3 houses. Mr.Brown can paint a house in 6 days while Mr.Black would take 8 days and Mr.Blue 12 days. After 8 days Mr.Brown goes on vacation and Mr. Black begins to work for a period of 6 days. How many days will it take Mr.Blue to complete the contract?

Answer: Option C

Explanation:

Here is no explanation for this answer

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Here is the list of questions asked in Cisco Aptitude Test Question with Answers Cisco Mock Test page 9. Practice Cisco Written Test Papers with Solutions and take Q4Interview Cisco Online Test Questions to crack Cisco written round test. Overall the level of the Cisco Online Assessment Test is moderate. Only those candidates who clear the written exam will qualify for the next round, so practic all the questions here and take all the free tests before going for final selection process of Cisco