# Placement Questions & Answers :: TCS

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641. Mother, daughter and infant total weight is 74 kg. Mother's weight is 46 kg more than daughter and infant's weight. Infant's weight is 60% less than daughter's weight. Find daughter's weight.

**Answer:**** Option A **

**Explanation:**

Total weight is M+D+I=74 given that M-D-I=46

solving above 2 eq's we get Mother weight = 60

Now reaming weight=14 which is sum of daughter and Infant weight. Given that Infant weight is 60% less than Daughter.

i.e If daughter weight is 100 then infant weight is 40. So weight ratio Of D and I is 100 : 40 i.e ... 5 : 2

So (5+2)=7 parts equal to 14. then 5 parts equal to 10.

2 parts equal to 4. daughter weight is =10 and infant weight is = 4

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642. In a particular year the month of January had exactly 4 Thursdays and 4 Sundays, on which day of the week, Jan 1 occurs?

**Answer:**** Option A **

**Explanation:**

As there are 4 full weeks i.e 28 days.

So, every day occurs min 4 times.

Then remaining 3 days (as jan has 31 days) will be Monday Tuesday Wednesday. so on 31st Jan comes Wednesday.

So, 1st Jan will be MONDAY

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643. Average salary of 17 teachers is 45000.3 teachers left and the average salary dropped by 2500.What is the sum of salaries of 3 teachers who left?

**Answer:**** Option C **

**Explanation:**

Total Initial Salary : 17*45000 = 765000

Average Salary After removal of 3 Teachers = 45000-2500 = 42500

Total Final Salary : 14*42500 = 595000

Sum of Salaries of 3 teachers who left : 765000 - 595000 = 170000

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644. Find a two digit number which is doubled and after that add +2 in it. and then reverse the number we would get the actual number.

(Example : xy * 2 = pq => pq+2 = xy )

**Answer:**** Option A **

**Explanation:**

Lets assume the two digit number be 10x+y

Adding 2 after doubling the number is reverse of the number.

So 2(10x+y)+2 = 10y+x

19x -8y +2=0 ----- (i)

The above equation (i) satisfies for the value, x=2, y=5

So, the number = 10*2+5= 25

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645. Let a, b, c, d and e be distinct integers in ascending order such that(76-a)(76-b)(76-c)(76-d)(76-e) = 1127. What is a + b + c + d

**Answer:**** Option B **

**Explanation:**

Product of 5 terms equal to 1127. As all the five terms are integers, given product should be a product of 5 numbers. Now factorize 1127.

1127 = 72 * 23 = 7 * 7 * 23

But given that all the a, b, c, d, e are distinct. And we are getting only 3 terms with 7 repeats.

Now the logic is, integers means positive and negative, 7 and - 7 possible and 1, - 1 also possible . As a,b, c, d, e are in ascending order, the factors should be in decreasing order. So (23, 7, 1, -1, -7)

Now a = 53; b = 69; c = 75; d = 77

a + b + c + d = 274.

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646. What is the average of the first 200 terms of the series

1, -2, 3, -4, 5, -6, 7......

**Answer:**** Option C **

**Explanation:**

1+3+5+7+9+11+13.........+199 i.e 100 terms and

sum of n odd natural numbers is n^2 i.e 100^2 =10,000

-(2+4+6+8+10+12...........+200) i.e 100 terms and

sum of n even natural numbers is n(n+1) i.e -(100(100+1))= -10,100

average of first 200 terms = (10,000+(-10,100))/200

=-100/200

=-1/2 Ans.

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647. If 43 times of two digit numbers is 34 times of two digit reverse no . and sum of number is 14 then what is the number?

**Answer:**** Option B **

**Explanation:**

43 time the no. And 34 time the reverse no.

43(10x+ y)=34(10y+ x)

430x+ 43y= 340y+34x

430x+43y-340y-34x=0

To solve this equation become

4x-3y=0 -------------- (1)

Sum of no. And reverse no. Is 14

X+ Y= 14 ------------- (2)

To solve both equation value of x and y

X= 6 and y= 8

So, number will be 68

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Here is the list of questions asked in TCS Aptitude Test Question with Answers TCS Mock Test page 65. Practice TCS Written Test Papers with Solutions and take Q4Interview TCS Online Test Questions to crack TCS written round test. Overall the level of the TCS Online Assessment Test is moderate. Only those candidates who clear the written exam will qualify for the next round, so practic all the questions here and take all the free tests before going for final selection process of TCS