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100 students appeared for two different examinations 60 passed the first, 50 the second and 30 both the examinations. Find the probability that a student selected at random failed in both the examination
A5/6
B1/5
C1/7
D5/7
Answer: Option B
Explanation:60+50-30=80
100-80=20
20/100=1/5.
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632 / 652
A mother her little daughter and her just born infant boy together stood on a weighing machine which shows 74kgs. How much does the daughter weight if the mother weighs 46kg more than the combined weight of daughter and the infant and the infant weighs 60% less than the daughter.
A9
B11
C10
DCannot be Determined
Answer: Option C
Explanation:Lets assume Daughter weight = x
infant weight is 60% less than daughter i.e., 0.4x mother weight is (x+0.4x+46)
Total weight = x + 0.4x + (x+0.4X+46) = 74
By solving the above eq.
x = 10
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633 / 652
How many positive integers less than 4300 of digits 0-4.
A560
B565
C575
D625
Answer: Option C
Explanation:one digit no =4 (0 is not a positive integer)
two digit no=4*5=20
three digit no=4*5*5=100
four digit no=3*5*5*5=375(the possibility for 1,2,3 will come in the first position)four digit no=1*3*5*5(the possibility of 4is fixed in the first position and then 0,1,2 is comes in second position)and the last digit is 4300 we include this number also
4+20+100+375+75+1=575
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634 / 652
A bag contains 8 white balls, and 3 blue balls. Another bag contains 7 white, and 4 blue balls. What is the probability of getting blue ball?
A3/7
B7/22
C7/25
D7/15
Answer: Option B
Explanation:First we have to select a bag and then we will draw a ball. Probability of selection of both bags is equal =1/2
Now probability of blue ball taken from first bag = ( 1/2) x (3/11) and probability of blue ball taken from second bag = (1/2) x (4/11) So probability of blue ball = ( 1/2) x (3/11) + (1/2) x (4/11) = 7/22
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635 / 652
In a 3*3 square grid comprising 9 tiles each tile can be painted in red or blue color. When the tile is rotated by 180 degree, there is no difference which can be spotted. How many such possibilities are there?
A16
B32
C64
D256
Answer: Option B
Explanation:Grid has to be rotated at 180 degrees. hence,
11=33
12=32
13=31
21=23
22=22
31=13
32=12
33=11
cell 11-33 can be altered in 2 ways (as thr are 2 colours)
cell 12-32 can be altered in 2 ways cell 13-31 can be altered in 2 ways cell 21-23 can be altered in 2 ways and , cell 22 can be altered in 2 ways.
so 2X2X2X2X2 = 32.
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636 / 652
1,2,2,3,3,3,4,4,4,4,1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4,4,4,…………………...
Then what is the 2320 position of the number in the sequence?
A2
B1
C3
D4
Answer: Option B
Explanation:1,2,3,4(1-1time 2- 2times 3-3 4-4)=10 terms /completes cycle and starts from 1
1,2,3,4(1-2 2-4 3-6 4-8)= 20 terms /completes cycle and starts from 1 (1,2,3,4)each digit 3 time to its value =30 terms/completes cycle and starts from 1
10+20+30+40+50+.......=x
x is nearer value to 2320 solving n(n+1)/2
10.(21.22)/2= 2310
analysing it 2310 completes cycle and starts from 1 again now it 22 times
(1-22 times 2-44 times ......)
2320 position will occupied by 1
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637 / 652
In a clock the long hand is of 8cm and the short hand is of 7cm. if the clock runs for 4 days find out the total distance covered by both the hands
A1824? cm
B1648? cm
C1724? cm
D2028? cm
Answer: Option B
Explanation:One full rotation in 12 hours =>2?r=14? cm traversed every 12 hours. For one day(24 hours ), we have 28? cm, twice that of a 12 hour period. For 3 days, we then have 4 x 28 ?=112? cm traversed.
Long Hand ( Minute hand)
One full rotation in 1 hour =>2?r=16? cm traversed every hour. For one day, we have 24 x 16 ?=384? cm.
For 4 days, we then have 4 x 384?=1536? cm traversed. Total Distance
For the total, we have 112?+1536?=1648? cm.
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638 / 652
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days A alone can finish the remaining work?
A7
B6
C5
D10
Answer: Option B
Explanation:Here is no explanation for this answer
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639 / 652
In how many way possible ways can you write 1800 as a product of 3 positive integers a,b,c
A350
B360
C380
D450
Answer: Option B
Explanation:1800=2^3*3^2*5^2
then 5c2*4c2*4c2=360
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Mother, daughter and infant total weight is 74 kg. Mother's weight is 46 kg more than daughter and infant's weight. Infant's weight is 60% less than daughter's weight. Find daughter's weight.
A10
B9
C8
D7
Answer: Option A
Explanation:Total weight is M+D+I=74 given that M-D-I=46
solving above 2 eq's we get Mother weight = 60
Now reaming weight=14 which is sum of daughter and Infant weight. Given that Infant weight is 60% less than Daughter.
i.e If daughter weight is 100 then infant weight is 40. So weight ratio Of D and I is 100 : 40 i.e ... 5 : 2
So (5+2)=7 parts equal to 14. then 5 parts equal to 10.
2 parts equal to 4. daughter weight is =10 and infant weight is = 4
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Here is the list of questions asked in TCS Aptitude Test Question with Answers page 64. Practice TCS Written Test Papers with Solutions and take Q4Interview TCS Online Test Questions to crack TCS written round test. Overall the level of the TCS Online Assessment Test is moderate. Only those candidates who clear the written exam will qualify for the next round, so practic all the questions here and take all the free tests before going for final selection process of TCS
