TCS Placement Questions & Answers :: TCS
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A bus leaves Mumbai at 3 pm. It travels for 1.5 hours at 60km/hr and then halts for 30 minutes. It then travels at an average speed of 50km/hr for the remaining duration to reach Pune at 6pm. What is the distance between Mumbai and Pune?
A100 km
B110 km
C120 km
D140 km
ENone of these
Answer: Option D
Explanation:bus covered a distance in (1.5 hour and 30 min. halt) 2 hour is = 1.5*60 = 90 km
Remaing time to reach pune is only 1 hour then bus travels with the speed of 50km/h
Now reamin. distance = 1*50 = 50 km
Now total 50+90 = 140 km
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582 / 652
Which of the following ratios is greatest?
A7/15
B9/17
C11/19
D13/21
E15/23
Answer: Option E
Explanation:Here is no explanation for this answer
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583 / 652
Rahul scored 75% marks in his board exams comprising 5 subjects. He applied for re-evaluation and got 25 marks in one subject, and 5 marks less in another subject. For the remaining three subjects, the marks were unchanged. What is his new percentage?
A75%
B77%
C79%
D70%
Answer: Option C
Explanation:5 subjects each subject 100 marks total = 500
Rahul got 75% .
=> 75% of 500 = 375
Total marks = 375+25-5 = 395
Average = (395/500)*100 = 79%
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584 / 652
A frog is in the bottom of a 20 m deep well. Every days it jumps 5 meters upwards and falls 4 meters down. How many days will it take for the frog to get out of the well?
A16
B20
C15
D19
E18
Answer: Option A
Explanation:1st day it jumps 5 meters and falls 4 meters, now will be at a height of 1 meter.
2nd day it jumps to 6 meters and falls back to 2 meter.
3rd day it jumps to 7 meters and falls back to 3 meter.
.....
.....
15th day it jumps to 19 meters and falls back to 15 meters.
Finally, 16th day it jumps to 20 meters, but now the frog have reached the top of the well.
Frog reaches top of the well at 16th day.
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585 / 652
1, 2, 3 and 4 can form 256 different four digit numbers. If digits repeated, two of them are 1111 and 1113. Then find the sum of 256 numbers.
A711040
B711000
C711038
D711042
Answer: Option A
Explanation:s = n/2(a+L)
s = 256/2(1111+4444)
s = 711040
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586 / 652
A sum of 20706 is distributed amongst A, B and C. A gets 10/123 of what B and C got together and C gets 1/10 of what A and B got together, C's share is (approx)?
A1454
B1881
C1882
DNone of these
Answer: Option B
Explanation:A+B+C=20706
A== 10/123 (B+C)
C=1/10 (A+B)
to find out C-
solve using the equation of C i.e C=1/10 (A+B)
=> A+B=10C
Substitute A+B=10C into the main equation i.e A+B+C=20706
Thus, 10C+C=20706
=> 11C=20706
=> C=1882.36 which is approximately 1882
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587 / 652
In paper A, one student got 18 out of 70 and in paper B he got 14 out of 30. In which paper he did fare well?
AB
BA
CBoth
DNone
Answer: Option A
Explanation:Paper A : (18/70)*100~=25.71%
Paper B : (14/30)*100~=46.66%
Therefore the solution is Paper B
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588 / 652
Three distinct single-digit numbers A,B and C are in geometric progression.
If abs(x) for real x is the absolute value of x (x if x is positive or zero and -x if x is negative ). Then the number of different possible values of abs(A+B-C) is:
A3
B5
C4
D6
Answer: Option B
Explanation:As given numbers are in GP,
So, numbers will be GP as 1, 1*3,1*3^2
abs(x) = x (as x is positive no.)
abs(1+3-9) = |1+3-9| = 5
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589 / 652
Hari has a piece of cake 60 cm long. He gives Raja half of it. He then gives Gopal 1/4th of what is left. After giving a piece to Sahi, be is left with 1/10th of the original. How much did he give to Sahil ?
A21.5 cm
B16.5 cm
C5 cm
D3 cm
Answer: Option B
Explanation:Given : Piece of cake = 60 cm long .
He gives Raja 1/2 of it = 1/2*60 = 30 cm long.
Left with Hari now = 60-30 = 30
He gives Gopal 1/4th of what is left = 1/4*30 = 7.5
Now left = 30-7.5 = 22.5
Now let he gave Sahil = x,
So, as per question:
22.5-x=1/10*60
=> x=16.5 cm is required.
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590 / 652
If a lemon and apple together costs Rs.12, tomato and a lemon cost Rs.4 and an apple costs Rs.8 more than a lemon. What is the cost of lemon?
A3
B2
C1
DNone of these
Answer: Option B
Explanation:Lets assume lemon as l, apple as a and tomato as t
As per question:
l+a=12
t+l=4
a=l+8
therefore, l+(l+8)=12
2l+8=12
2l=12-8
l=2
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Here is the list of questions asked in TCS Aptitude Test Question with Answers page 59. Practice TCS Written Test Papers with Solutions and take Q4Interview TCS Online Test Questions to crack TCS written round test. Overall the level of the TCS Online Assessment Test is moderate. Only those candidates who clear the written exam will qualify for the next round, so practic all the questions here and take all the free tests before going for final selection process of TCS