TCS Placement Questions & Answers :: TCS
551 / 652
I lost my wallet and the money in that. But I remember that before I lost my wallet I purchased two things. First one I purchased by paying 10% of what in my wallet and also for second one I also pay 10% of what has been left in my wallet, that is equal to 9. Then how much money I lost?
A81
B54
C63
D25
Answer: Option A
Explanation:Assume Lets total amount = 'x'
10% is spent on 1st item
=> amount spent on 1st item = x*(10/100) = x/10
So, amount left = x-(x/10) = 9x/10
Given: %of amount spent on 2nd item = 10%
Amount spent on 2nd item = 9
So, amount spent on 2nd item = (9x/10)*(10/100) = 9
=> x =100
Money left in the wallet = money lost
x-(x/10)-9 = money lost
100-(100/10)-9=81
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552 / 652
If the area of a square region having sides of length 6 cms is equal to the area of a rectangular region having width 2.5 cms, then the length of the rectangle, in cms, is?
A41
B14
C14.4
D13
Answer: Option C
Explanation:area of square region = area of rectangular region
side*side=length*width
6*6=2.5*length
hence length=(6*6)/2.5
14.4 square cm
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553 / 652
If a, b and c are forming increasing terms of G.P., r is the common ratio then find the minimum value of (c-b), given that (log a+log b+log c)/log 6 = 6.
Note that r can be any real no.
A36
B24
C12
D18
Answer: Option A
Explanation:(log a + log b + log c)/log 6 = 6
(log abc )/log 6 = 6
log6 abc=6
abc = 6^6
From gp series a/r * a * ar =6^6
a^3= 6^6
a=36
so, a= 36/r, b=36, c=36r
c-b = 36r-36
=36(r-1)
Given r can be real number.
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554 / 652
The ratio between the number of sheep and the number of horses at the Stewar farm is 4 to 7. If each of horse is fed 230 ounces of horse food per day and the farm needs a total 12880 ounces of horse food per day. what is number sheep in the form??
A18
B28
C32
D56
Answer: Option C
Explanation:Lets assume no. of sheep and horses are 4k and 7k
No. of horses= 12880/230 = 56
Now 7K = 56 and k = 8
No. of sheep = (4*8) = 32
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555 / 652
3 dice are rolled. what is the probability of getting sum as 13?
A21/216
B1/216
C15/216
D1/36
Answer: Option A
Explanation:(6,6,1)=3 ways
(6,5,2)=6 ways
(5,5,3)=3 ways
(4,4,5)=3 ways
(6,4,3)=6 ways
Hence total ways = 21
So, probability = 21/(6*6*6) = 21/216
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556 / 652
On selling mangoes at 36 for a rupee, a shopkeeper loses 10%. How many mangoes should he sell for a rupee in order to gain 8%?
A30
B43
C23
D33
Answer: Option A
Explanation:Selling price of one mango = 1/36
New selling price = (1/36)*(108/90) = 1/30
So,for 1?, he should sell 30 mangoes.
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557 / 652
Find the number of zeros in the expression:
15*32*25*22*40*75*98*112*125
A1
B6
C9
D7
Answer: Option C
Explanation:Do the multiple of Numbers as below:
15 = 3*5
32 = 2*2*2*2*2
25 = 5*5
22 = 2*11
40 = 2*2*2*5
75 = 5*5*3
98 = 2*7*7
112 = 2*2*2*2*7
125 = 5*5*5
you will get 0 when 2 is multiplied by 5
and total no. of 2's are 14 and 5's are 9
so no. of zeroes is according to 5 as it is minimum.
so, answer will be 9
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558 / 652
Three partners X,Y, Z start the business. Y's capital has been four times Z's capital also twice X's capital has been equal to three time Y's capital. In case total profit has been Rs. 16500 at end of the year. Find out Y's share in it.
ARs. 9000
BRs. 6000
CRs. 1500
DNone of these
Answer: Option B
Explanation:As per questions:
Y's capital has been four times Z's capital
Y=4Z ---(i)
twice X's capital has been equal to three time Y's capital
2X=3Y =>Y= 2X/3 ---(ii)
To get the ratio of X, Y, Z.
From (i) & (ii)
2X/3 = 4Z => Z=X/6
So X : Y : Z = X : 2X/3 : X/6 = 6 : 4 : 1
So, Y's share in Rs. 16500 = (4/11)*16500 =Rs. 6000
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559 / 652
The current age difference between two persons is 25. 9 years before the elder one's age was 6 times that of the younger one. What is sum of their current ages?
A39 Years
B14 Years
C25 Years
D53 Years
Answer: Option D
Explanation:Lets assume younger age = x Years.
So, elder age will be (as per question) = (x+25) years.
Given:
(X+25)-9 = 6(X-9)
By Solving the above eqaution
=> x=14 whicjh is the age of younger
elder = 25+14 = 39 years.
sum of their current ages = 39+14 = 53
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560 / 652
A person travels from Chennai to Pondicherry in cycle at 7.5 Kmph. Another person travels the same distance in train at a speed of 30 Kmph and reached 30 mins earlier. Find the distance.
A5 Km
B10 Km
C15 Km
D20 Km
Answer: Option A
Explanation:Let the distance be x kms.
then A/Q,
x/(7.5) - x/(30) =30/60 => x= 5 Km.
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