MindTree Aptitude Questions and Answers for Freshers
1 / 60
A can do a piece of work in 14 days which B can do in 21 days. They begin together but 3 days before the completion of the work, A leaves off. The total number of days to complete the work is:
A6 3/5
B8 1/2
C10 1/5
D13 1/2
Answer: Option C
Explanation:A's 1 day work = \(\frac{1}{14}\)
B' 1 day work = \(\frac{1}{21}\)
A left 3 day before the completion of work.
B's 3 days' work = \(\frac{1}{21} \times 3 = \frac{1}{7}\)
Remaining work = \(1 \times \frac{1}{7} = \frac{6}{7}\)
(A + B)'s 1 day's work = \(\left(\frac{1}{14} + \frac{1}{21}\right) = \frac{5}{42}\)
Now, \(\frac{5}{42}\) work is done by A and B = 1 day.
or
whole work done by A&B = \(\frac{42}{5}\)
\(\frac{6}{7}\) part of work done by A and B = \(\frac{42}{5} \times \frac{6}{7} = \frac{36}{5}\) days.
Hence, total time taken = (3+36/5)days = \(10\frac{1}{5}\) days.
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2 / 60
A vendor bought toffees at 6 for a rupee. How many for a rupee must he sell to gain 20%?
A3
B4
C5
D6
Answer: Option C
Explanation:C.P. of 6 toffees = Re. 1
S.P. of 6 toffees = 120% of Re. 1 = Rs. (120/100 ) = Rs. 6/5
so toffees in Re 1 = 6 * 5/6 = 5
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3 / 60
In a certain company, 20% of the men and 40% of the women attended the annual company picnic. If 35% of all the employees are man, what percent of all the employees went to the picnic?
A33.33%
B34%
C30%
D33%
Answer: Option D
Explanation:Lets assume that total 100 employees are in company.
out of that 35 are man and remaining 65 are women.
20% of man 35 = 20*35/100
40% of women = 40*65/100
total employees = 7+26 = 33 out of 100
=> 33 %
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4 / 60
In seven given numbers,the average of first four numbers is 4 and that of last four numbers is also 4. If the average of these seven numbers is 3, the fourth number is?
A3
B4
C7
D11
Answer: Option D
Explanation:let 7 numbers are a,b,c,d,e,f,g.
given avg of first 4 nums are 4...i.e (a+b+c+d)/4=4
a+b+c+d=16
given avg of last 4 nums are also 4..i.e.(d+e+f+g)/4=4
d+e+f+g=16
e+f+g=16-d
given avg of 7 nums are 3....i.e (a+b+c+d+e+f+g)/7=3
a+b+c+d+e+f+g=21
16+16-d=21
d=32-21
d=11
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5 / 60
The boys and girls in a college are in the ratio 3 : 2. If 20% of the boys and 25% of the girls are adults, the percentage of students who are not adults is :
A58%
B67.50%
C78%
D82.50%
Answer: Option C
Explanation:let total students will be 100 divide it in 3:2 =60/40
20 % 60=12 boys adult
25 % 40= 10girls adults
total adults = 22
no of students =100
100-22=78
78% are non adult
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6 / 60
In June a baseball team played 60 games and won 30% of them. After a phenomenal winning streak this team raised its average to 50%. How many games must the team have won in a row to attain this average?
A30
B24
C12
D20
Answer: Option B
Explanation:explanation: 60----18 wins (18/60)*100=30%.
for 50% they are winning games in row= ((18+x)/(60+x))*100=50%
by solving this we will get x= 24 games.
here x= no of winning games in a row
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7 / 60
There are 3 boys and 4 girls. How many ways they are arranged such that boys should be always together ?
A5 ways
B6 ways
C120 ways
D720 ways
Answer: Option D
Explanation:By keeping 3 boys together (1) and arranging 4 girls with them
5! = 5*4*3*2*1 = 120ways. (i.e., 4+1 =5)
Possible arrangements of 3 boys in following ways
3! = 3*2*1 = 6ways
Now, arrange all with the boys together
120*6 = 720ways
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8 / 60
3 balls inside a bag having numbers on it written 1, 2, 3 on it. A ball is taken and then put inside it. Find probability that all 3 nos. are the same when it is taken 3 times?
A1/26
B1/27
C1/6
D1/12
Answer: Option B
Explanation:By law of probability = 1/3 * 1/3 * 1/3 = 1/27
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9 / 60
Find the coordinates of the midpoint of the line segment joining the points A(-3,2) and B(7,8)
A2,4
B3,3
C2,5
D4,3
ENone of above
Answer: Option C
Explanation:mid point of two point
take two point a(x1,y1) and b(x2,y2)
so mid point is (x1+x2)/2 and (y1+y2)/2
so (-3+7)/2=4/2=2
and (2+8)/2=10/2=5
so mid point is (2,5)
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10 / 60
An article costing rs.160 is sold at 15% discount on a mark-up price. What is the selling price after discount?
A124
B126
C136
D140
Answer: Option C
Explanation:As 100 % of CP = 160
100-15 % of CP = SP = (160*85)/100 = 136
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