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George while driving along the highway saw road markers which are at equal distances from each other. He crosses the markers every 20 seconds. If he increases his speed by x meters per second, he crosses the markers at every 15 seconds. But if he increases his speed by y meters per second, he crosses the marker at every 10th second. If y-x = 40 meters per second, then what is the distance between two markers.


A1100

B1200

C1301

D1220

Answer: Option B

Explanation:

Let speed be =z m/s then Distance= 20z m (z+x)15=20z; (z+y)10=20z

Also given that y - x = 40 solving we get 20z=1200

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The value of a scooter depreciates in such a way that its value of the end of each year is 3/4 of its value of the beginning of the same year. If the initial value of the scooter is Rs.40,000, what is the value at the end of 3 years ?


ARs.13435

BRs.23125

CRs.19000

DRs.16875

Answer: Option D

Explanation:

40,000(34)3=16875

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There are 3 classes having 20, 24 and 30 students respectively having average marks in an examination as 20, 25 and 30 respectively. The three classes are represented by A, B and C and you have the following information about the three classes.

a. In class A highest score is 22 and lowest score is 18

b. In class B highest score is 31 and lowest score is 23

c. In class C highest score is 33 and lowest score is 26.


If five students are transferred from A to B, what can be said about the average score of A; and what will happen to the average score of C in a transfer of 5 students from B to C?


Adefinite decrease in both cases

Bcan't be determined in both cases

Cdefinite increase in both cases

Dwill remain constant in both cases

Answer: Option B

Explanation:

Class A average is 20. And their range is 18 to 22 Class B average is 25. And their range is 23 to 31 Class A average is 30. And their range is 26 to 33

If 5 students transferred from A to B, A's average cannot be determined but B's average comes down as the highest score of A is less than lowest score of B.

If 5 students transferred from B to C, C's average cannot be determined the B's range fo marks and C's range of marks are overlapping.

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A city in the US has a basketball league with three basketball teams, the Aziecs, the Braves and the Celtics. A sports writer notices that the tallest player of the Aziecs is shorter than the shortest player of the Braves. The shortest of the Celtics is shorter than the shortest of the Aziecs, while the tallest of the Braves is shorter than the tallest of the Celtics. The tallest of the Braves is taller than the tallest of the Aziecs.

Which of the following can be judged with certainty?

X) Paul, a Brave is taller than David, an Aziec
Y) David, a Celtic, is shorter than Edward, an Aziec


ABoth X and Y

BX only

CY only

DNeither X nor Y

 View Answer |  Submit Your Solution | Topic: Uncategorized| Asked In TCS |

Answer: Option B

Explanation:

Let the shortest of Braves is 4 feet. Then tallest of Aziecs is less than 4. So let it be 3 feet.

A -> 2 - 3
B -> 4 - 6
C -> 1 - 7

From the above we can safely conclude X is correct.
But Y cannot be determined.

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Raj goes to market to buy oranges. If he can bargain and reduce the price per orange by Rs.2, he can buy 30 oranges instead of 20 oranges with the money he has. How much money does he have?


ARs.100

BRs.50

CRs.150

DRs.120

Answer: Option D

Explanation:

Here is no explanation for this answer

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How many different 9 digit numbers can be formed from the number 223355888 by re-arranging its digits so that the odd digits occupy even position?


A65 ways

B45 ways

C12 ways

D60 ways

Answer: Option D

Explanation:

Odd places are 4 and these are occupied by 3355. So this can be done in 4!/ (2! 2!) = 6 There are 5 even numbers which have to be placed at 5 odd places. So 5!/(2!3!) = 10 ways so total number of ways of arranging all these numbers are 10 * 6 = 60 ways

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Seven different objects must be divided among three persons. In how many ways this can be done if at least one of them gets exactly one object.


A186

B190

C120

D196

Answer: Option D

Explanation:

Division of m+n+p objects into three groups is given by (m+n+p)!m!*n!*p! But 7 = 1 + 3 + 3 or 1 + 2 + 4 or 1 + 1 + 5

So The number of ways are (7)!1!*3!*3!*12! + (7)!1!*2!*4! + (7)!1!*1!*5!*12! = 70 + 105 + 21 = 196

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Anusha, Banu and Esha run a running race of 100 meters. Anusha is the fastest followed by Banu and then Esha. Anusha, Banu and Esha maintain constant speeds during the entire race. When Anusha reached the goal post, Banu was 10m behind. When Banu reached the goal post Esha was 10m behind. How far was behind Anusha when the latter reached the goal post.


A70

B81

C90

D80

Answer: Option B

Explanation:

By that time Anusha covered 100m, Bhanu covered 90m. So ratio of their speeds = 10 : 9 By that time Bhanu reached 100m, Esha covered 90m. So ratio of their speeds = 10 : 9 Ratio of the speed of all the three = 100 : 90 : 81

By that time Anusha covered 100m, Esha Covers only 81.

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Rajiv can do a piece of work in 10 days , Venky in 12 days and Ravi in 15 days. They all start the work together, but Rajiv leaves after 2 days and Venky leaves 3 days before the work is completed. In how many days is the work completed?


A5

B6

C9

D7

Answer: Option D

Explanation:

Let the work be 60 units. If venky leave 3 days before the work, Last 3 days must be worked by Ravi.
So the remaining days of work be x days,
Total days to complete the work be x + 3 days.

Now Capacities of Rajiv is 60/10 = 6,
Venky is 5,
Ravi is 4. (6 + 5 + 4) 2 + (5 + 4) (x - 3) + 4 x 3 = 60.

30 + 9x - 27 + 12 = 60 9x - 15 =30

9x = 45 x = 5

So total days to complete the work = 2 + 5 = 7 days.

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Mark told John "If you give me half your money I will have Rs.75. John said, "If you give me one third of your money, I will have Rs.75/- How much money did John have?


A45

B60

C48

D37.5

Answer: Option B

Explanation:

Let the money with Mark and John are M and J respectively. Now

M + J/2 = 75 M/3 + J = 75

Solving we get M = 45, and J = 60.

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