# Placement Questions & Answers :: TCS

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351. Apples cost L rupees per kilogram for the first 30 kilograms and Q per kilogram for each additional kilogram. If the price paid for 33 kilograms of Apples is Rs.1167 and for 36 kilograms of apples if Rs.1284, then the cost of the first 10 kgs of apples is:

**Answer:**** Option B **

**Explanation:**

By question

30L + 3Q = 1167 ------ (1)

30L + 6Q = 1284 -------(2)

By solving eq. (1) & (2)

Q = 39, L = 35

So, cost of first 10 kgs of apples = 35 * 10 = Rs. 350

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352. A and B can do a piece of work in 40 days. Thier skills of doing the work are in the ratio 8:5. how many days will A take to engage alone ?

**Answer:**** Option A **

**Explanation:**

Ratio of efficiency of A:B=8:5

Total Efficiency=13

They complete the work in 40 days

When the efficiency of A is 8

A could complete the work in (40/8)*13=65 days

Thus. A alone can do the work in 65 days

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353. A number increased 37 1/2% gives 33. So, the number is

**Answer:**** Option C **

**Explanation:**

Let x be that number

x+(37 1/2 % of x)=33

x+3x/8=33

11x=33*8

x=33*8/11=24

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354. Smallest no which when multiplied by 12748 gives a perfect square is

**Answer:**** Option A **

**Explanation:**

Here is no explanation for this answer

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355. what is the unit digit of(2^3)^123456

**Answer:**** Option D **

**Explanation:**

(2^3)^123456=2^370368

Take unit position of power

2^8=256

so unit position is 6

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356. Jake and paul start together to walk 10kms jake walks 1.5kmph faster than paul and arrives at his destination 1.5 hours earlier than paul jakes speed walking is

**Answer:**** Option C **

**Explanation:**

Let speed of jake = x kmph.

So, speed of paul = ( x - 1.5 ) kmph.

Time difference =1.5hours

Total Distance = 10km

10/(x-1.5) -10/x = 1.5

By solving the above eq.

x = 4 kmph

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357. Find the number of zeros in the expression 15*32*25*22*40*75*98*112*125.

**Answer:**** Option A **

**Explanation:**

Expen 15*32*25*22*40*75*98*112*125 as below

(3*5)*(2^5)*(5^2)*(11*2)*(5*2^3)*(3*5^2)*(49*2)*(7*2^4)*(5^3)

Total no. of 5 = 9 & n.o of 2=14

So, Total number of zero = 9

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358. If a^x= b , b^y= c and c^z = a , then what is the value of x*y*z ?

**Answer:**** Option A **

**Explanation:**

((((a)^x)^y)^z)=a

so.(a)^xyz=a

so xyz=1

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359. In how many ways a team of 11 must be selected a team 5 men and 11 women such that the team must comprise of not more than 3 men.

**Answer:**** Option B **

**Explanation:**

Here is no explanation for this answer

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360. How many liters of a 90% of concentrated acid needs to be mixed with a 75% solution of concentrated acid to get a 30 liter solution of 78% concentrated acid?

**Answer:**** Option C **

**Explanation:**

concentration is given which is wrt 100, hence we can take x lt of 90% and (30-x)of 75%

x*90 + (30-x)*75 = 30*78 hence the ans is 6 ltr.

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Here is the list of questions asked in TCS Aptitude Test Question with Answers TCS Mock Test page 36. Practice TCS Written Test Papers with Solutions and take Q4Interview TCS Online Test Questions to crack TCS written round test. Overall the level of the TCS Online Assessment Test is moderate. Only those candidates who clear the written exam will qualify for the next round, so practic all the questions here and take all the free tests before going for final selection process of TCS