1 / 58
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
A120 metres
B180 metres
C324 metres
D150 metres
Answer: Option D
Explanation:Length of the train = (Speed x Time) =50/3 x 9 m = 150 m.
Workspace
2 / 58
A 600m long train is running at 73 Kmph. How much time Train will take to cross an electric pole?
A29.58 sec
B28.58sec
C29 sec
D28sec
ENone of these
Answer: Option A
Explanation:Formula Used: Time = ( Distance / Speed)
As all the option given in sec., so convert the train speed (Kmph) in to mps multiply by 5/18
speed (mps) = 73 * 5/18
Time = 600 / (73 * 5/18)
= (600 * 18 )/(73 * 5) sec
= (10800 / 365)
Time take by Train = 29.58Sec
Workspace
3 / 58
A 120 m long train is running at 72 Kmph. How much time will it take to cross a man standing on the platform?
A6 sec
B2.5 sec
C5 sec
D12 sec
Answer: Option A
Explanation:Formula Used: Time = ( Distance / Speed)
As all the option given in sec., so convert the train speed (Kmph) in to mps multiply by 5/18
speed (mps) = 72 * 5/18 = 20 mps
Time = (120 / 20) sec = 6 sec
Time take by Train = 6 Sec.
Workspace
4 / 58
A train running at speed of 126 Kmph. What will be the length of train if it cross a tree in 5 sec.
A190 meters
B180 meters
C143 meters
D175 meters
ENone of these
Answer: Option D
Explanation:Formula Used: Distance = (Speed * Time)
convert the train speed (Kmph) in to mps multiply by 5/18
speed (mps) = 126 * 5/18 = 35 mps
length = ( 35 * 5 ) meter
= 175 meter
Workspace
5 / 58
320m long train is running at 72 Kmph. how much time it will take to cross a platform of 180m long?
A20 sec
B30 sec
C25 sec
D27 sec
Answer: Option C
Explanation:Total Length = Platform Length + Train Length
So Total Length = 500m
convert the train speed (Kmph) in to mps multiply by 5/18
speed (mps) = 72 * 5/18 = 20mps
Formula Used: Time = Distance/Speed
Time = (500 / 20 ) sec
= 25 sec
Workspace
6 / 58
Two trains 400m and 300m long run at the speeds of 50 kmph and 40kmph respectively in opposite Directions on parallel tracks. The time taken to cross each other?
A20 sec
B28 secs
C25 sec
D24 sec
ENone of these
Answer: Option B
Explanation:Trains are running in opposite Direction:
So need to find Length of two Trains = 300m + 400m = 700m
and Total Speed = 40 Kmph + 50 Kmph (Opposite Direction)
= 90 Kmph
so speed (m/sec) = 90 * 5/18 m/sec = 25 m/sec
Formula Used: Time = Distance/Speed
Time = 700/ 25 sec
Time = 28 Sec
Workspace
7 / 58
A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 19 and 20 seconds respectively. The length of the train is:
A245 m
B211.1 m
C210 m
D213 m
Answer: Option B
Explanation:Convert the persons Speed in m/sec
2 kmph = (2 x 5/18) m/sec = 5/9 m/sec.
4 kmph = (4 x 5/18 m/sec = 10/9 m/sec.
Let the length of the train be x meters and its speed by y m/sec.
Relative speed in respect to both person (y - 5/9) and (y - 10/9)
Formula Used: Time = Distance / speed
so x / (y - 5/9) = 19 ---- (1)
and x / (y - 10/9) = 20 ---- (2)
9x = 19 (9y - 5) ----- (1)
9x = 20 (9y - 10) ------(2)
find the value of x and y
19 (9y - 5) = 20(9y - 10)
171 y - 95 = 180 y -200 => 9y = 105 => y = 105/9 = 35/3
Now find the value fo x by above any equations
9x = 171 *35/3 - 95 = 57 *35 - 95
9x = 1900 => x = 211.1 meter
Workspace
8 / 58
Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
A10 a.m.
B11 a.m.
C10 p.m.
D11 p.m.
Answer: Option A
Explanation:Let they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
So Total Distance
=> 20x + 25(x - 1) = 110
=> 45x - 25 = 110 => 45x = 135
=> x = 3.
As They meet x hrs after 7 a.m. so they meet at 10 a.m.
Workspace
9 / 58
A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The other one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. If both the persons are walking in the same direction as the train? So What is the speed of the train ?
A96 km/hr
B51 km/hr
C81 km/hr
D76 km/hr
Answer: Option C
Explanation:Convert the Speed in m/sec
so 4.5 km/hr = ( 4.5 x 5/18 ) m/sec = 5/4 m/sec = 1.25 m/sec,
and 5.4 km/hr = ( 5.4 x 5/18 ) m/sec = 3/2 m/sec = 1.5 m/sec.
Here assume the speed of the train as x m/sec.
so relative will be (x-1.25) and (x - 1.5)
(x - 1.25) x 8.4 = (x - 1.5) x 8.5
=> 8.4x - 10.5 = 8.5x - 12.75
=> 0.1x = 2.25
=> x = 22.5 m/s
As options are given in km/hr so convert the speed mps to kmph
So Speed of the train = ( 22.5 x 18/5 ) km/hr = 81 km/hr.
Workspace
10 / 58
Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?
A27 m
B33 m
C27 7/9 m
D23 4/9 m
Answer: Option C
Explanation:As train are running in same direction
so Relative speed = (40 - 20) km/hr = 20 km/hr
= ( 20 x 5/18 ) m/sec = 50/9 m/sec.
Formula Used: Distance = Speed * Time
Now Length of Faster Train = ( 50/9 x 5 ) m = 250/9 m
= 27 7/9 m
Workspace
In this practice section, you can practice Arithmetic Aptitude Questions based on "Problems on Trains" and improve your skills in order to face the interview, competitive examination, IT companies Written exam, and various other entrance tests (CAT, GATE, GRE, MAT, Bank Exam, Railway Exam etc.) with full confidence.
Q4Interview provides you lots of fully solved Arithmetic Aptitude (Problems on Trains) questions and answers with Explanation. Solved examples with detailed answer description, explanation are given and it would be easy to understand. You can download Arithmetic Aptitude Problems on Trains quiz questions with answers as PDF files and eBooks.
Here you can find objective type Arithmetic Aptitude Problems on Trains questions and answers for interview and entrance examination. Multiple choice and true or false type questions are also provided.