Solution: 2 red, 3 green, and 2 blue balls are there. So the probability of getting no blue ball is not selecting any blue ball among the two chosen balls hence 5C2.
5C2/7C2 = 10/21.
7C2 because we can select any 2 balls from 7 balls in that number of ways.
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64
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10 men and 10 women are there, they dance with each other, is there possibility that 2 men are dancing with same women and vice versa.
Solution: Because it is written that 10 men and 10 women dance with each other. So there is no chance of matching more than 2 partners at a time. So 2 men
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40
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There is a toy train that can make 10 musical sounds. It makes 2 musical sounds after being defective. What is the probability that same musical sound would be produced 5 times consecutively?
For the FIFA world cup, Paul the octopus has been predicting the winner of each match with amazing success. It is rumored that in a match between 2 teams A and B, Paul picks A with the same probability as A's chances of winning. Let's assume such rumors to be true and that in a match between Ghana and Bolivia, Ghana the stronger team has a probability of 2/3 of winning the game. What is the probability that Paul will correctly pick the winner of the Ghana-Bolivia game?
Let Paul picks Ghana then probability that its prophecy will be true is 2/3*2/3 =4/9.
Now it may pick up Bolivia and the chances of winning are 1/3*1/3=1/9
So total probability will be 4/9 1/9=5/9
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After the typist writes 12 letters and addresses 12 envelopes, she inserts the letters randomly into the envelopes (1 letter per envelope). What is the probability that exactly 1 letter is inserted in an improper envelope?
If one letter is put in a wrong envelope, then one other letter must also be put in the wrong envelope. So zero is the probability that exactly 1 letter is inserted in an improper envelope because it's not possible.
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In a lottery, there are 10 prizes and 25 blanks. A lottery is drawn at random. What is the probability of getting a prize?
A no. is divisible by 4 if last two digit is divisible by 4
so numbers ending with 24,28,48,52,56,64,68,84 are divisible by 4
last two places are fixed by 24,28,48,52,56,64,68,84
so remaining 3 places can be filled in 3! ways for each
total=8*3!=48=n(E)
n(S) = 5!
so
= n(E)/n(S)
=48/120=2/5
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