Arithmetic Aptitude :: Chain Rule

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On a map the distance between two mountains is 3 1 2 inches. The actual distance between the mountains is 136 km. Ram is camped at a location that on the map is 3 4 inch from the base of the mountain. How many km is he from the base of the mountain?

A13.50 km

B14.82 km

C12.82 km

DNone of these

Explanation:

since 312 inch=136 km
so 1 inch=136/312 km
so 34 inch=136*34/312=14.82 km.

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Grass in lawn grows equally thick and in a uniform rate. It takes 24 days for 70 cows and 60 for 30 cows . How many cows can eat away the same in 96 days?

A18

B20

C21

D19

Explanation:

Let g = grass initially, r = rate at which grass grow/day and c= cow eat grass/day.
=> g + 24r = 70 * 24c = 1680c -----------(i)
and,
=> g + 60r = 60 * 30c = 1800c
=> g = 1800c - 60r -----------(ii)
By solving these equations, we have c = (3/10)r -------------(iii)
=> g + 96r = 96nc.
=> 96nc = 1800c - 60r + 96r = 1800c + 36r=1800c+120c=1920c
=>n=20.

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in a grass field, If there are 40 cows, they could eat for 40 days. If there are 30 cows, they could eat for 60 days. Than if 20 cows, How much day they could eat?

A98 Days.

B80 Days.

C67 Days.

D87 Days.

Explanation:

40 cows take 40 Days.
and 30 cows take 60 Days.
Its obvious that 10 cows less 20 days More.
So, 20 Cows will take 80 Days.

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A person can buy 50 cds with $135 and 15 dvds with$100 Nikita has a budget of $1680 for cds & budget of$150 for dvds How many cds & dvds in total can she buy?

A624

B688

C644

D642

Explanation:

cds = (50*1680)/135=622 apprx
dvds = (150*15)/100=22 apprx
Total=644 apprx

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A constructor estimates that 3 people can paint Mr. khans house in 4 days. If he uses 4 people instead of 3,how long will they take to complete the job?

A4

B2

C3

D5

Explanation:

Lets assume day required to complete the job = x day

Men Day
---------------------
3(u) 4(d)
4 x
x/4 = 3/4
=> x = 3 days.

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3 men and 8 women complete a task in same time as 6 men and 2 women do. How much fraction of work will be finished in same time if 4 men and 5 women will do that task.

A6/ 13

B7/11

C13/14

D11/12

Explanation:

3M + 8W = 6M + 2W ---------(1)
solving this we get
M = 2W
Therefore 3M + 8W = 14W
4M + 5W =13W
=>fraction of work is 13/14

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A bread making machine can be make bread of 50 kg dough in 3 minutes. How many such machines are required to make breads of 300kg dough in 6 minutes

A6

B3

C4

D5

Explanation:

Lets assume x machine required to make breads of 300 kg dough in 6 min.

Note: (u) means up arrow and (d) means down arrow.

-------------------------------
1(d) 50 kg. (d) 3 min. (u)
x 300 kg. 6 min.

=> x/1 = 300/50 * 3/6
=> x = 3 Machine

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A stock of rice is enough for 100 men for 60 days. How long will the same stocks of rice last for 500 men:

A9 days

B5 days

C6 days

D10 days

E12 days

Explanation:

Men Days
----------------------
100 (u) 60 (d)
500 x

100/500 = x/60
=> x = (100/500) * 60 = 12 days.

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A play school has chocolates which can supply 50 students for 30 days. For the first ten days only 20 students were present. How many more students can be accommodated into the earlier group such that the entire chocolates get consumed in 30 days. Assume each student takes the same number of chocolates.

A45

B60

C55

D70

Explanation:

Let each students gets 1 chocolate.
Total chocolates = 50 * 30 = 1500
If first 10 days only 20 students were present, then total chocolates consumed = 10 * 20 = 200
Now we are left with 1500 - 200 = 1300 chololates. These were to be consumed in 20 days.
So each day 1300/20 = 65 chocolates were to be distributed.
So we can add 65 - 20 = 45 students.

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Apples cost L rupees per kilogram for the first 30 kilograms and Q per kilogram for each additional kilogram. If the price paid for 33 kilograms of Apples is Rs.1167 and for 36 kilograms of apples if Rs.1284, then the cost of the first 10 kgs of apples is:

ARs.117

BRs.350

CRs.281

DRs.1053

Explanation:

By question
30L + 3Q = 1167 ------ (1)
30L + 6Q = 1284 -------(2)
By solving eq. (1) & (2)
Q = 39, L = 35
So, cost of first 10 kgs of apples = 35 * 10 = Rs. 350

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