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What will be the output of the below C program.
#include<stdio.h>
int main()
{
int i=-1;
+i;
printf("i = %d, +i = %d \n",i,+i);
return 0;
}
#include<stdio.h>
int main()
{
int i=-1;
+i;
printf("i = %d, +i = %d \n",i,+i);
return 0;
}ACompilation Error
Bi=-1, +i=0
Ci = -1, +i = -1
DNone of these
Answer: Option (Login/Signup)
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STEP-BY-STEP
In line no 4, variable i is initialized with -1.
Line no. 5 is basically of no use, you may delete it if you like, it will work the same.
In the next line it will print i=-1 and +i=+(-1), which is equal to -1.
So, the output will be i = -1, +i = -1.
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