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What will the following program do?
#include<stdio.h>
#include<string.h>
#include<malloc.h>
int main(){
int i;
char a[]="String";
char *p="New Sring";
char *Temp;
Temp=a;
a=malloc(strlen(p) + 1);
strcpy(a,p); //Line no:9//
p = malloc(strlen(Temp) + 1);
strcpy(p,Temp);
printf("(%s, %s)",a,p);
free(p);
free(a);
return 0;
}
Chose correct option
#include<stdio.h>
#include<string.h>
#include<malloc.h>
int main(){
int i;
char a[]="String";
char *p="New Sring";
char *Temp;
Temp=a;
a=malloc(strlen(p) + 1);
strcpy(a,p); //Line no:9//
p = malloc(strlen(Temp) + 1);
strcpy(p,Temp);
printf("(%s, %s)",a,p);
free(p);
free(a);
return 0;
}
Chose correct optionASwap contents of p and a and print
BGenerate compilation error in line number 8
CGenerate compilation error in line number 5
DGenerate compilation error in line number 7
EGenerate compilation error in line number 1
Answer: Option (Login/Signup)
Show Explanation
malloc allocation need to be assigned to char pointer instead of char array. a=malloc(strlen(p) + 1);
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malloc allocation need to be assigned to char pointer instead of char array. a=malloc(strlen(p) + 1);
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