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The value of a scooter depreciates in such a way that its value of the end of each year is 3/4 of its value of the beginning of the same year. If the initial value of the scooter is Rs.40,000, what is the value at the end of 3 years ?
ARs.13435
BRs.23125
CRs.19000
DRs.16875
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This question is belong to G.P.
So,
here
a = 40000
r = 2/3
n = 3
Tn = ?
Formula:
Tn = ar^n-1
T3 = 40000 (2/3)^3-1
T3 = 40000(2/3)^2
T3 = 40000(4/9)
T3 = 17777.77
Ans.
So,
here
a = 40000
r = 2/3
n = 3
Tn = ?
Formula:
Tn = ar^n-1
T3 = 40000 (2/3)^3-1
T3 = 40000(2/3)^2
T3 = 40000(4/9)
T3 = 17777.77
Ans.
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