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In this problem, ABS(x) provides absolute value of x, without regard to its sign. For example ABS(3) = ABS(-3) = 3
The graphs of y = – ABS(x – a) + b and y = – ABS(x – c) + d intersect at points (2,5) and (8, 3).
Find a + c

A8

B10

C7

D5

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