# Arithmetic Aptitude :: progressions

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## 10. A ball dropped from H height and moves 80% of height each time. Total distance covered is

**Answer:**

**Option D**

**Explanation :**

First time distance= H

Second time = 80H/100 = 4H/5

similarly third time 80% of 4H/5 = H(4^2)/(5^2)

and so on..

This will lead to infinite terms of geometric progression

i.e H+2*4H/5+2*16H/25..

So, Sum = H+ 2*4H/(5(1-4/5)) = 9H

**Asked In :: **
Accenture

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