Arithmetic Aptitude :: progressions
10. A ball dropped from H height and moves 80% of height each time. Total distance covered is
First time distance= H
Second time = 80H/100 = 4H/5
similarly third time 80% of 4H/5 = H(4^2)/(5^2)
and so on..
This will lead to infinite terms of geometric progression
So, Sum = H+ 2*4H/(5(1-4/5)) = 9H