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Quantitative Aptitude :: Time and Distance - Discussion

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Choose the correct option.

A man driving his bike at 24 kmph reaches his office 5 minutes late. Had he driven 25% faster on an average he would have reached 4 minutes earlier than the scheduled time. How far is his office?

A24 km

B72 km

C18 km

DData Insufficient

Answer: Option (Login/Signup)

Show Explanation

Let x km be the distance between his house and office. 

While travelling at 24kmph, he would take x/24  hours. 

While travelling at 25% faster speed,

i.e. 24 25% of 24=24×(1/4)=30 kmph, he would take x/30 hr



Now as per the problem, time difference = 5 min late 4 min early = 9 min

x/24-x/30=9 min



Solving this we get â‡’ x= 18 km



 

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