Quantitative Aptitude :: Problems on Trains - Discussion

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Explanation:
speed of the faster train = 2x m/sec.
Relative speed of train = (x + 2x) m/sec = 3x m/sec.
Total distance = (100 + 100)m = 200m
3x = 200/8
=> 24x = 200 => x = 25/3
So speed of the faster train = 2 * 25/3 m/sec
= 50/3 m/sec
= 50/3 * 18/5 = 60 km/hr.