C Programming :: Declarations and Initializations - Discussion
Home > C Programming > Declarations and Initializations > MCQs Questions Discussion
38 / 54
Choose the correct option.
In case of ordinary int variables
Aleftmost bit is reserved for sign
Brightmost bit is reserved for sign
Cno bit is reserved for sign
DNone of these
Answer: Option (Login/Signup)
Show Explanation
Asked In ::
STEP-BY-STEP
An ‘int’ is actually 1 sign bit + 31 data bits, i.e, 31 bits are available for storing the number being assigned to a ‘int’ type variable and 1 bit(leftmost bit) is reserved for maintaining the sign of the number which is either '+' or '–' . The sign is also represented by binary digits, '0' for positive sign and '1' for negative sign.
Read Full Answer
Report Error
Please Login First Click Here