Quantitative Aptitude :: Pipes & Cistern - Discussion

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Explanation:
Let ‘f’ m^3/min be the filling capacity of the pump. Therefore, the emptying capacity of the
pump will be = (f + 10 ) m^3/ min.
The time taken to fill the tank will be = 3600/f minutes
And the time taken to empty the tank will be = 3600/(f+10).
We know that it takes 12 more minutes to fill the tank than to empty it
=> 3600/f - 3600/(f+10) = 12
=> 36000 = 12 (f^2 + 10 f) => 3000
=> f^2 + 10f - 3000 = 0
Solving for positive value of ‘f’ we get, f = 50.
So, the emptying capacity of the pump = 50 + 10 = 60 m