Quantitative Aptitude :: Numbers - Discussion

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Explanation:
For a 2nd degree equation "ax2+bx-c=0" has equal roots the condition is b2-4ac =0
So in the given equation (2kx^2 + 5kx +2)
a=2k, b=5k, c=2

=> (5k)^2-4(2k)(2)=0
=> 25k^2-16k=0
=>k(25k-16)=0
=> k=16/25;