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What does the following function return, if q contains the address of the first element?

int function(NODE *q)
{ 
int c = 0;
while( q != NULL)
{ 
q = q->link;
c++;
} 
return (c);
} ?

AThe value of the last node of the linked list

BThe value of the first elements of the linked list

CThe address of the last element of the linked list

DThe number of elements in a linked list

Answer: Option (Login/Signup)

Show Explanation

Consider list1 and list2 linked lists given below:

list1: 15 -> 18 -> 25 -> 30

list2: 11 -> 14 -> 17 -> 23 -> 32 -> 56

What will be the elements of the queue that is returned by the code snippet given below when list1 and list2 are passed as arguments to function, fun?

def fun(input_list1,input_list2):   

 temp1 = input_list1.get_head()   

 temp2 = input_list2.get_head()  

  output_queue = Queue(10)   

 while(temp1 != None and temp2 != None):    

    if(temp1.get_data() < temp2.get_data()):         

   output_queue.enqueue(temp1.get_data())          

  temp1 = temp1.get_next()      

  elif(temp1.get_data() > temp2.get_data()):         

   output_queue.enqueue(temp2.get_data())       

     temp2 = temp2.get_next()     

   else:          

  output_queue.enqueue(temp2.get_data())          

  temp1 = temp1.get_next()           

 temp2 = temp2.get_next()   

 while(temp1 != None):       

 output_queue.enqueue(temp1.get_data())       

 temp1 = temp1.get_next()    

while(temp2 != None):       

 output_queue.enqueue(temp2.get_data())       

 temp2 = temp2.get_next()

  return output_queue

Note: Order of displaying the queue elements is from front to rear.  

Select one:

Asked In :: Sopra Steria Capgemini

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