Quantitative Aptitude :: Numbers - Discussion
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In school there are some bicycles and 4 wheeler wagons. One Tuesday there are 58 wheels in the campus. How many bicycles are there?
A2
BBoth C & D
C5
D7
Show Explanation
Let there are B bicycles and W wagons.
Total number of wheels = 2 × B 4 × W
Given 58 wheels ⇒ 2B 4W = 58
⇒ B 2W = 29 …… (Eq.1)
Also given B W = 18 …… (Eq.2)
∴ Eq.1 – Eq.2
⇒ W = 11
⇒ B = 18 – W
⇒ B = 18 – 11 = 7 Bicycles.
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Solution: 2b 4w = 58 whereb= bicycles and w= wagons
There are two answers possible to it- 5, 7
It can easily be done by option verification
Put 5 or 7 in place of b in the equation, we get a whole number value of w.
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Let there are B bicycles and W wagons.
Total number of wheels = 2 × B 4 × W
Given 58 wheels ⇒ 2B 4W = 58
⇒ B 2W = 29 …… (Eq.1)
Also given B W = 18 …… (Eq.2)
∴ Eq.1 – Eq.2
⇒ W = 11
⇒ B = 18 – W
⇒ B = 18 – 11 = 7 Bicycles.
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The answer can also be 5. Since 5x2=10.
58-10=48 which is perfectly divisible by 4. 12 cars and 5 bicycles.
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