C Programming :: Declarations and Initializations - Discussion

syntax is wrong

printf() should end with ; and there is no closing quotes for character literals

correct format is

printf((x>7)?"%d":"%c",i); then result will be 'k'

if it prints k then code  need to be correct first as your answer.(termination and double quotes not present)

#include

void main()

{

int i = 107, x = 5;

printf ((x > 7)? "%d" : "%c:", i);

}

printf ((x > 7)? "%d" : "%c:, i) x value assigned is 5 hence 5 is not greater than 7 so second condition i.e (%c:i)

will be executed means ascii value of small k is 107 so the character k will be printed. 

Here in line no. 5, (x>7) will result to false as 5 is not greater than 7. So, %c part will get executed, meaning that the value of i won't be displayed, rather the character whose ASCII value corresponds to 107 i.e, 'k' will get displayed, hence option C is correct.

if it print k, then code should be like this as your answer.

#include

void main()

{

int i = 107, x = 5;

printf ((x > 7)? "%d" : "%c:", i);

}