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# Practice Questions & Answers :: AMCAT

351.88K

## Total Practice Qs: 308+

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21 / 308

Choose the correct option.

If abc4d is divisible by 4, then d cannot be:

A0

B4

C8

D2

| | Important Formulas | Topic: | Asked In WiproAMCAT |

Explanation:

40,44,48 is divisible by 4.
not 42. hence d cannot be 2

Tags: Wipro

NA
SHSTTON
79
Solv. Corr.
31
Solv. In. Corr.
110
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22 / 308

Choose the correct option.

A and B invest money in the ratio 3:4 and they has loss of Rs.7000 at the end of year. what is the share of loss of B?

ARs.4000

BRs.3000

CRs.7000

DRs.2000

| | Important Formulas | Topic: | Asked In Tech MahindraAMCAT |

Explanation:

Share of loss of B = 7000 *4/7 = Rs. 4000

NA
SHSTTON
28
Solv. Corr.
30
Solv. In. Corr.
58
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23 / 308

Choose the correct option.

A jar contains 2 red, 3 blue, and 4 green marbles. Niki draws one marble from the jar, and then Tom draws a marble. What is the probability that Niki will draw a green marble and Tom will draw a blue marble?

A1/6

B2/8

C5/6

D3/8

| | Important Formulas | Topic: | Asked In IBMAMCAT |

Explanation:

P(green, blue) = 4/9 * 3/8 = 1/6

Tags: IBM

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24
Solv. Corr.
28
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52
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Choose the correct option.

The base of a triangular field is three times its altitude. If the cost of cultivating the field at Rs. 24.68 per hectare be Rs. 333.18, find its base and height.

ABase = 100 m & Height = 200m.

BBase = 900 m & Height = 300m.

CBase = 1900 m & Height = 300m.

DBase = 900 m & Height = 1300m.

| | Important Formulas | Topic: | Asked In AMCAT |

Explanation:

Area of the field = Total cost/Rate = (333.18/24.68) hectares =13.5 hectares.
= (13.5*10000) m^2 =135000m^2.
Let altitude = x meters and base = 3x meters.
Then, 1/2 *3x* x= 135000 or x^2 = 9000 or x= 300.
Therefore, base =900 m & altitude = 300m.

Tags: No Tags on this question yet!

NA
SHSTTON
37
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39
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76
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25 / 308

Choose the correct option.

(0.1*0.1*0.1 + 0.02*0.02*0.02)/(0.2*0.2*0.2 + 0.04*0.04*0.04) is equal to

A0.125

B0.25

C0.5

D0.855

| | Important Formulas | Topic: | Asked In AMCAT |

Explanation:

Lets assume 0.1 as a so 0.2 will be 2a
and 0.02 as b so 0.04 will be 2b
Simplify the give equation
(a*a*a + b*b*b)/(2a*2a*2a+2b*2b*2b) => (a^3+b^3)/(8*a^3+8*b^3)
=> (a^3+^3)/8(a^c+b^3) = 1/8 = 0.125

Tags: No Tags on this question yet!

NA
SHSTTON
26
Solv. Corr.
44
Solv. In. Corr.
70
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26 / 308

Choose the correct option.

If (a^2 + b^2 + 1/a^2 + 1/b^2) = 4, then the value of (a^2 + b^2) will be

A1

B2

C1 1/2

D2 1/2

| | Important Formulas | Topic: | Asked In AMCAT |

Explanation:

Given (a^2 + b^2 + 1/a^2 + 1/b^2) = 4
Simplify the above eq.
=> a^2 + 1/a^2 +b^2 + 1/b^2 = 4
=> (a-1/a)^2 + 2 + (b - 1/b)^2 + 2 = 4
=> (a-1/a)^2 + (b - 1/b)^2 = 0
=> (a - 1/a) = 0; (b - 1/b) = 0
=> a = b = (+-)1
so (a^2+b^2) = 1+1 = 2

Tags: No Tags on this question yet!

NA
SHSTTON
25
Solv. Corr.
66
Solv. In. Corr.
91
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Choose the correct option.

if (2x + 2/x) = 1, then the value of (x^3 + 1/x^3) is

A13/8

B11/8

C-11/8

D-13/8

| | Important Formulas | Topic: | Asked In Global EdgeAMCAT |

Explanation:

(2x + 2/x) = 1
=> (x + 1/x) = 1/2
(x^3+1/x^3) = (x+1/x)^3-3x*1/x(x+1/x)
= (1/2)^3-1/2 = (1/8 - 3/2) = (1-12)/8= -11/8

Tags: Global Edge

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45
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Choose the correct option.

If A:B = 2:3, B:C = 4:5 and C:D = 5:9,then A:D is equal to

A11:17

B8:27

C5:9

D2:9

| | Important Formulas | Topic: | Asked In Global EdgeAMCAT |

Explanation:

A/B*B/C*C/D= 2/3*4/5*5/9
=> A/D = 8/27

Tags: Global Edge

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Choose the correct option.

For what values of 'm' is y = 0, if y = x^2 + (2m + 1)x + m^2 - 1? x is a real number.

Am >= -2

Bm < 0

Cm = 0

Dm >= -1.25

| | Important Formulas | Topic: | Asked In AMCAT |

Explanation:

Here is no explanation for this answer

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14
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Choose the correct option.

Rs.432 is divided amongst three workers A, B and C such that 8 times A's share is equal to 12 times B's share which is equal to 6 times C's share. How much did A get?

ARs. 134.

BRs. 140.

CRs. 144.

DRs. 212.

| | Important Formulas | Topic: | Asked In AMCAT |

Explanation:

8 times A's share = 12 times B's share = 6 times C's share.
Note that this is not the same as the ratio of their wages being 8 : 12 : 6

In this case, find out the L.C.M of 8, 12 and 6 and divide the L.C.M by each of the above
numbers to get the ratio of their respective shares.

The L.C.M of 8, 12 and 6 is 24.
Therefore, the ratio A:B:C :: 24/8 : 24/12 : 24/6
=> A : B : C :: 3 : 2 : 4

The sum of the total wages = 3x + 2x + 4x = 432 => 9x = 432 or x = 48.
Hence A gets 3 * 48 = Rs. 144.