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AMCAT
Tot. Mock Test: 87+
Tot. Exam. Sec.: 4+
Total Practice Qs: 308+
11 / 308
A two-digit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. The number is:
A18
B24
C42
D81
Answer: Option B
Explanation:Check the options, by subtracting 18 from each option for getting reverse number.
42 - 18 = 24 (which is in reverse)
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12 / 308
The ratio of marks obtained by vinod and Basu is 6:5. If the combined average of their percentage is 68.75 and their sum of the marks is 275, find the total marks for which exam was conducted.
A100
B200
C150
D180
Answer: Option B
Explanation:Let Vinod marks be 6x and Basu's is 5x. Therefore, the sum of the marks = 6x + 5x = 11x.
But the sum of the marks is given as 275 = 11x. We get x = 25 therefore, vinod marks is 6x = 150and Basu marks = 5x = 125.
Therefore, the combined average of their marks = (150 + 125) / 2 = 137.5.
If the total mark of the exam is 100 then their combined average of their percentage is 68.75
Therefore, if their combined average of their percentage is 137.5 then the total marks would be
(137.5 / 68.75)*100 = 200.
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13 / 308
In an exam, Ajith, Sachu, Karna, Saheep and Ramesh scored an average of 39 marks. Saheep scored 7 marks more than Ramesh. Ramesh scored 9 fewer than Ajith. Sachu scored as many as Saheep and Ramesh scored.Sachu and Karna scored 110 marks them. If Ajith scores 32 marks then how many marks did Karna score?
A53 marks
B23 marks
C57 marks
D30 marks
Answer: Option C
Explanation:Lets assume marks of Ajith, Sachu, Karna, Saheep and Ramesh respectively u, v, w, x, y So, as per the question: z+7=x ---(i) u- 9=z ---(ii) x+ z=v ---(iii) v+w=110 ---(iv) Given, u=32 ---- (v) By solving eq. (i), (ii), (iii), (iv) and (v) w=57
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14 / 308
The average set of numbers is 46, if 4 numbers whose average is 52 are subtracted from this set,the average becomes 44.5.find the original number in the set?
A22
B20
C18
D16
Answer: Option B
Explanation:Let us consider total no's in a set = n.
Sum of set= 46 * n.
=> 46*n-4*52=44.5*(n-4)
=> 46n-208=44.5n-178
=> 1.5n=30 =>n=20.
Hence, total no. in a set = 20.
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15 / 308
The average of 7 numbers is 50. The average of three of them is 40, while the average of the last three is 60. What must be the remaining number
A40
B60
C50
D55
Answer: Option C
Explanation:Sum of last 3 numbers=180.
Sum of other 3 numbers=120.
Sum of all seven numbers=350.
=> 180+120+x=350
=> x=50.
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16 / 308
The two trains of lengths 400m, 600m respectively, running at same directions. The faster train can Cross the slower train in 180sec, the speed of the slower train is 48km. then find the speed of the Faster train?
A58 Kmph
B78 kmph
C55 Kmph
D68 Kmph
Answer: Option D
Explanation:Length of the two trains = 600m + 400m = 1000m
Let's Assume Speed of the first train = x kmph
Speed of the second train= 48 Kmph
So Relative Speed = (x - 48) kmph =((x -48) * 5/18) m/sec
1000/((x -48) * 5/18) = 180
18000/(5x - 240) = 180
100 = 5X - 240
=> 5x = 340 => x = 68 kmph
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17 / 308
On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is:
ARs. 45
BRs. 50
CRs. 55
DRs. 60
Answer: Option D
Explanation:(C.P. of 17 balls) - (S.P. of 17 balls) = (C.P. of 5 balls)
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18 / 308
A scooterist covers a certain distance at 36 kmph. How many meters does he cover in 2 min?
A800 meters.
B1100 meters.
C700 meters.
D1200 meters.
Answer: Option D
Explanation:Speed = 36 kmph = 36 * 5/18 = 10mps
So, Distance covered in 2 min = (10 * 2 * 60)m = 1200 meters.
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19 / 308
The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 km in 4 hours, then the speed of the first train is:
A70 km/hr
B75 km/hr
C84 km/hr
D87.5 km/hr
Answer: Option D
Explanation:Let the speed of two trains be 7x and 8x km/hr.
Then, 8x = 400/4 = 100
=> x = 100/8 = 12.5.
So, the speed of first train = (7 x 12.5) km/hr = 87.5 km/hr.
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20 / 308
Two-third of one-seventh of a number is 87.5% of 240. Whar is the number?
A2670
B2450
C2205
D1470
ENone of these
Answer: Option C
Explanation:Lets assume no. = x
2/3 * 1/7 * x = 87.5*240/100
By solving
x= 2205
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