# Accenture Placement Questions & Answers :: Accenture

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61 / 136

**Choose the correct option.**

In a election between two candidate 10% of votes were invalid winner got 70% of valid votes and was elected by a majority of 900 votes. find the total number of votes?

A2600

B2200

C2500

D2550

**Answer:**** Option C **

**Explanation:**

Lets assume votes = x

valid votes are 0.9x,

Given 70% of 0.9x is 900 more than 30% of 0.9x,

=> 0.9*0.7-900=0.3*0.9x

=> x=2500

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62 / 136

**Choose the correct option.**

log base 12 144p=3 then p= ?

A12

B13

C15

D11

**Answer:**** Option A **

**Explanation:**

log base 12 144p=3

=> 144p=12^3

=> 144p=12^2 *12

=> 144p=144*12

=> p=12

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63 / 136

**Choose the correct option.**

3 men and 8 women complete a task in same time as 6 men and 2 women do. How much fraction of work will be finished in same time if 4 men and 5 women will do that task.

A6/ 13

B7/11

C13/14

D11/12

**Answer:**** Option C **

**Explanation:**

3M + 8W = 6M + 2W ---------(1)

solving this we get

M = 2W

Therefore 3M + 8W = 14W

4M + 5W =13W

=>fraction of work is 13/14

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64 / 136

**Choose the correct option.**

The sum of ages of suresh and his father is 78 years.6 years hence father's age will be twice of suresh's age. Find present age of father.

A54 years

B45 years

C55 years

DNone of these

**Answer:**** Option A **

**Explanation:**

Lets assume suresh age = x years.

So, father age = (78-x) years.

Condition : 6 years hence

2* (x + 6) = (78 - x + 6)

=> 2x + 12 = 84 - x

=> 3x = 72

x = 24 years.

Father age = 78 - 24 = 54 years.

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65 / 136

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In this question A^B means A raised to the power of B Start with the integers from 1 to 10^2012. Replace each of them by the sum of its digits to get a string of 10^2012 numbers. Keep doing this until you get 10^2012 single digit numbers. Let m be the number of 1's and n be the number of 2's. Then m - n

A1

B2

C3

D0

**Answer:**** Option A **

**Explanation:**

We divide all the numbers into groups of 9. (1 to 9), (10 to 18).....

Now when we divide each term in the first group by 9, we get 1, 2, 3 ..0 as remainders. Now digit sum is nothing but finding remainder when a number is divided by 9. So the last term, 10^2012 gives remainder 1 when divided by 9. So there is one "1" extra than 2's.

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66 / 136

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Two trains A and B start simultaneously from stations X and Y towards each other respectively. After meeting at a point between X and Y,train A reaches station Y in 9 hours and train B reaches station X in 4 hours from the time they have met each other. If the speed of trainA is 36 km/hr, what is the speed of train B?

A24 km/hr

B54 km/hr

C81 km/hr

D16 km/hr

**Answer:**** Option B **

**Explanation:**

Naming the trains as A and B. Then,

(A's speed) : (B's speed) = (b : a)^.5

where b and a is the time taken by trains B and A, to reach their destination after they meet.

hence,

36/B's speed = (4: 9)^.5

=> B's speed = 54km/hr

**ShortCut By ::**

**yogen**

s1/s2=underroot(t2/t1)

s1/s2=underroot(4/9)

s1/s2=2/3

in question value of 2 is 36kmph

therefore value of 3 i.e s2 will be 54kmph

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67 / 136

**Choose the correct option.**

Five different roads join a village to nearby city. The no. of different ways in which a person can go to town and come back is ?

A25 ways

B35 ways

C22 ways

D45 ways

**Answer:**** Option A **

**Explanation:**

If we choose 1st road, To come back we have 5 ways..

similarly for 2nd,3rd,4th,5th road.

so total ways = 5+5+5+5+5 = 25 ways

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68 / 136

**Choose the correct option.**

Which of the following values of 'n' satisfies the in-equality n2 - 24n + 143 < 0?

An < 11

Bn > 13

C11 < n < 13

D11 > n > 13

ENone of these

**Answer:**** Option C **

**Explanation:**

n^2 - 24n + 143 < 0

=> (n-11)(n-13) < 0

=> 11 < n < 13

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69 / 136

**Choose the correct option.**

A car starts from rest and accelerates uniform upto speed 90 km/hrs in 5 sec. Total distance covered by car in this time will be

A62.5 m

B60 m

C54.5 m

DNone of these

**Answer:**** Option A **

**Explanation:**

Speed of car at last instant of given interval

= 90*5/ 18 m/s = 25 m/s

so average speed = 0+25 / 2

Therefore distance = 5 * 25/2 = 125/2 = 62.5 m

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70 / 136

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In a bid two firms A and B competing against each other.If the probability of bid amount quoted by B being lower than that of A is 0.8 and if it is known that the bid is won by the ones who quotes the lowest price,what is the probability that A wins the bid?

A0.8

B0.004

C0.2

D0.001

**Answer:**** Option C **

**Explanation:**

Probability of 'a' biding lower than 'b' = 1 - 0.8 = 0.2

so probability of wining of 'a' = 0.2

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Here is the list of questions asked in Placement Papers of Accenture Recent Placement Papers of Accenture. Practice Accenture Written Test Papers with Solutions and take Q4Interview Accenture Online Test Questions to crack Accenture written round test. Overall the level of the Accenture Online Assessment Test is moderate. Only those candidates who clear the written exam will qualify for the next round, so practic all the questions here and take all the free tests before going for final selection process of Accenture