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# Arithmetic Aptitude :: Calendar

Home > Arithmetic Aptitude > Calendar > General Questions

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41. The calendar for the year 2007 will be the same for the year:

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Explanation:

Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.

Sum = 14 odd days = 0 odd days.

Therefore, Calendar for the year 2018 will be the same as for the year 2007.

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42. On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?

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Explanation:

The year 2004 is a leap year and therefore, two days will be preceded from Tuesday i.e Sunday.

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43. The last day of a century cannot be

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Explanation:

100 years contain 5 odd days.
Last day of 1st century is Friday.
200 years contain (5 * 2) = 3 odd days.
Last day of 2nd century is Wednesday.
300 years contain (5 * 3) = 15 = 1 odd day.
Last day of 3rd century is Monday.
400 years contain 0 odd day.
Last day of 4th century is Sunday.
This cycle is repeated.
Last day of a century cannot be Tuesday or Thursday or Saturday.

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44. Curious Elva asked her father what he would gift for her nineteenth birthday. Father replied that it would depend on the day of the week and be one of SUNglasses, MONeybag, ..., FRIedcake, and SATchel. Please help Elva find the day of the week on 08-Jan-2029

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Explanation:

Number of odd days upto 2000 = 0
From 2001 to 2028 = 28 + 7 = 35 = 0 ( 35/7 remainder zero)
From 2019 January 1 to 7 = 7 = 0
So 08 - Jan - 2029 falls on the same week day as 1-1-1 which is Monday.

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45. In 2003, there are 28 days in February and there are 365 days in the year. In 2004, there are 29 days in February and there are 366 days in the year. If the date March 11, 2003 is Tuesday, then which on of the following would the date March 11, 2004 be?

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Explanation:

March 11, 2003 is Tuesday. So March 11, 2004 weekday will be 2 days after Tuesday. i.e., Thursday.

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46. A man has a job, which requires him to work 8 straight days and rest on the ninth day. If he started work on Monday, find the day of the week on which he gets his 12th rest day.

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Explanation:

He works for 8 days and takes rest on the 9th day.
So On the 12th rest day, there are 9 x 12 = 108 days passed.
Number of odd days = (108 - 1) / 7 = 107 / 7 = 2.
So the 12th rest day is Wednesday.

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47. In a particular year the month of January had exactly 4 Thursdays and 4 Sundays, on which day of the week, Jan 1 occurs?

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