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11. On the first test of the semester, kiran scored a 60. On the last test of the semester, kiran scored 75%. By what percent did kiran's score improve?
Answer: Option D
Explanation:In first test kiran got 60
In last test he got 75.
% increase in test = (60(x+100))/100=75
=> 0.6X+60 = 75
=> 0.6X = 15
=> X=15/0.6 = 25%
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12. A candidate who gets 20% marks fails by 10 marks but another candidate who gets 42% marks gets 12% more than the passing marks. Find the maximum marks.
Answer: Option D
Explanation:Let the maximum marks be x.
From the given statement pass percentage is 42% - 12% = 30%
By hypothesis, 30% of x - 20% of x = 10 (marks)
i.e., 10% of x = 10
Therefore, x = 100 marks.
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13. Randy's chain of used car dealership sold 16,400 cars in 1998. If the chain sold 15,744 cars in 1999, by what percent did the number of cars sold decrease?
Answer: Option B
Explanation:Let percentage of decrease is x , then
=> 16400(100-x)/100=15744
=> 16400-15744=164x
=> x=656/164 = 4%
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14. 5/9 part of the population in a village are males. If 30% of the males are married, the percentage of unmarried females in the total population is:
Answer: Option B
Explanation:Let the population =x Males=(5/9)x
Married males = 30% of (5/9)x = x/6
Married females = x/6
Total females = (x-(5/9)x)=4x/9
Unmarried females = (4x/9 - x/6) = 5x/18
Required percentage = (5x/18 * 1/x * 100) = (250/9)%
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15. In an election contested by two parties, Party D secured 12% of the total votes more than Party R. If party R got 132,000 votes, by how many votes did it lose the election?
Answer: Option D
Explanation:Let the percentage of the total votes secured by Party D be x%
Then the percentage of total votes secured by Party R = (x – 12)%
As there are only two parties contesting in the election, the sum total of the votes secured by the
two parties should total up to 100%
i.e., x + x – 12 = 100
2x – 12 = 100
or 2x = 112 or x = 56%.
If Party D got 56% of the votes, then Party got (56 – 12) = 44% of the total votes.
44% of the total votes = 132,000 i.e. 44/100 * T = 132,000
T = (132000 * 100)/44 = 300000 votes.
The margin by which Party R lost the election = 12% of the total votes
= 12% of 300000 = 36000.
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16. Increase area of a square by 69% by what percent should the side be incresed
Answer: Option D
Explanation:Area of square=x^2
Then area of increase=100+69=169
square root of 169 i.e 13 .
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17. The boys and girls in a college are in the ratio 3:2. If 20% of the boys and 25% of the girls are adults, the percentage of students who are not adults is:
Answer: Option C
Explanation:Suppose boys = 3x and girls = 2x
Not adults = (80*3x/100) + (75*2x/100) = 39x/10
Required percentage = (39x/10)*(1/5x)*100 = 78%
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18. A persons salary is decreased by steps of 20%, 15% and 10%. What will be the percentage decrease, if the salary is decreased in a single shot?
Answer: Option B
Explanation:decrease in salary in single shot =38.8%
first decease =20% let the salary be 100 then it will become 80
2nd decrease is= 15%. 15% of 80 =12 then salary become 68
3rd decrease is of 10% . 10% of 68 =6.8.then salary become 61.2
so overall decrease=38.8%
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19. In a society of 80 resident families who subscribe newspapers, 60% of them subscribe The Hindu newspaper, 80% of them subscribe regional language newspaper and 70% of them subscribe TOI. How many families could, at the least, be subscribing to all the three newspapers
Answer: Option C
Explanation:Total no. of families who take newspaper=80
Hindu newspaper = 60% = (80*60/100) = 48
Regional newspaper = 80% = (80*80/100) = 64
TOI newspaper = 70% = (70*80/100) = 56
Find common families take H.C.F (48,64,56) = 8
Therefore,(8/80)*100=10%
So, common families who take all newspaper = 10%.
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20. A survey of a village showed that 1 / 10 of the total population speak neither Hindi nor English. 1 / 5 of them cannot speak English and 3 / 7 of them cannot speak Hindi. What percentages of people know only one language?
Answer: Option A
Explanation:persons who can speak English = 1 - (1/5) = 4/5
persons who can speak Hindi = 1 - (3/7) = 4/7
persons who can speak any or both = 1 - 1/10 = 9/10
so total persons speak both = 4/5 + 4/7 - 9/10 = 33/70
persons speak any = 1 - 33/70 - 1/10 = 3/7
% = 300/7% = 42.86%
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