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1. The G.C.D. of 1.08, 0.36 and 0.9 is:
Answer: Option C
Explanation:Given numbers are 1.08 , 0.36 and 0.90
H.C.F of 108, 36 and 90 is 18 ( G.C.D is nothing but H.C.F)
So H.C.F of given numbers = 0.18
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Tags: nagarro
2. There are three numbers, these are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. What will be the sum of three numbers :
Answer: Option A
Explanation:Given that numbers are co primes,
and two products have the middle number in common.
=> Middle number = H.C.F. of 551 and 1073 = 29
so first number is = 551/29 = 19
=> Third number = 1073/29 = 37
Therefore, sum of these numbers is = (19 + 29 + 37) = 85
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Tags: nagarro
3. What is the largest number that will divide 90207, 232585 and 127986 without leaving a remainder?
Answer: Option A
Explanation:Find the HCF of given numbers.
90207=3*3*3*13*257
127986=2*3*83*257
232585=5*181*257
HCF is 257.
So larget number without leaving a remainder is 257
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Tags: TCS
4. The H.C.F of two numbers is 11 and their L.C.M is 7700. If one of the numbers is 275, then the other is:
Answer: Option A
Explanation:lcm*hcf = product of 2 nos
11*7700=275*?
ans =308
ShortCut By :: rlcm*hcf = product of 2 nos
11*7700=275*?
ans =308
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Tags: Infosys Global Edge
5. Let p and q be two prime numbers such that p is greater than q. If 319 is their LCM then the difference of thrice of q and p is:
Answer: Option C
Explanation:Solution: We know that HCF of two prime numbers is 1.
Product of HCF and LCM = 1 x 319 = 319.
Remember that, Product of two number = Product of their HCF and LCM
pq = 319
Now, co-primes with product 319 are (1,319) and (29,11)
Since p > q, p = 29 and q = 11
Then 3q - p = 3 - 29 = 4.
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Tags: IBM Global Edge
6. Let 13 and 273 are the HCF and LCM of two numbers respectively, and if one of them is less than 140 and greater than 60 then what will be that number?
Answer: Option B
Explanation:Solution: Product of two number = Product of their HCF and LCM
pq = 13*273
pq = 3549.
Now, co-primes with product 3549 are (1,3549), (21,169), (39,91) and (13,273)
Acc. to the condition given in the question only one satisfy them that is (39,91)
So the answer is 91.
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Tags: IBM
7. Sudhir goes to the market once every 64 days and Sushil goes to the same market once every 72 days. They met each other one day. How many days later will they meet each other again?
8. Sum of squares of two numbers is 2754, their HCF is 9, LCM is 135, Find the numbers
Answer: Option B
Explanation:Product of two no. = H.C.F*L.C.M
So,x*y=135*9=1215 -----(1)
and x^2+y^2=2754
So,(x+y)^2=x^2+y^2+2*x*y = 2754+2*1215=5184
So,x+y=72 ----------- (2)
By solving eq. (1) & (2)
nos. are 45 and 27
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Tags: Wipro Global Edge
9. Find the largest 4-digit number, which gives the remainder 7 and 13 when divided by 11 and 17?
Answer: Option B
Explanation:LCM of 11 and 17 = 187.
When divided by 11 remainder 7,so difference 4.
When devided by 17 remainder 13,so difference 4.
Largest no exactly devide by 11 & 17=9911
The no's = 9911-4 = 9907.
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Tags: Wipro Global Edge
10. Printer A prints 8192 character per min and printer B prints 13862 character per min four character are equal to one word. Printer A starts at 7:15 am while Printer B starts at 7:29 am then at what time both will have same no. of words printed.
Answer: Option B
Explanation:Four character are equal to one word
8192/4*(t+14)=13862/4*t
8192*(t+14)=13862*t yields the same result
t=20.2272 minutes = about 20 min 14 sec
7:49:14 am
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Tags: IBM