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Basic Concepts Questions

NA
SHSTTON
109
Solv. Corr.
320
Solv. In. Corr.
429
Attempted
1 M:2 S
Avg. Time

1 / 64

What will happen when you attempt to compile and run the following code?
public class MyField{
String s;
public static void main(String argv[]){
        MyField m = new MyField();
        m.amethod();
        }
void amethod(){
        System.out.println(s);
        }
}

ACompile time error s has not been initialised

BRuntime error s has not been initialised

CBlank output

DOutput of null

Answer: Option D

Explanation:

The above code will compile fine, no problem in that, but the output will be null, since variable 's' has not been initialized with some value.

Hence, output will be null.

Workspace

NA
SHSTTON
450
Solv. Corr.
122
Solv. In. Corr.
572
Attempted
0 M:6 S
Avg. Time

2 / 64

What will be the output of the below code segement:
String[] elements = {"Java","is","platform","independent"};
String result = (elements.length > 0) ? elements[0]:null;
System.out.printf(result);

Aindependent

Bjava

Cis

Dplatform

Answer: Option B

Explanation:

The condition (elements.length>0) will result to True, since the length size of elements array is 4, which is greater than 0.

Therefore, elements[0] will be stored in result, or we can simply say, result = "Java".

hence, output will be Java.

Workspace

NA
SHSTTON
435
Solv. Corr.
123
Solv. In. Corr.
558
Attempted
0 M:40 S
Avg. Time

3 / 64

What will be the output of the below code segement:
public class SwitchTest {
public static void main(String argv[]) {
SwitchTest ms=new SwitchTest();
ms.display();
}
public void display() {
        int k=10;
        switch(k){
            
            default:
            System.out.println("This is the default output");
            break;
            case 10:
            System.out.println("ten");
            break;
            case 20:
            System.out.println("twenty");
            break;
        }
    }
}

Aten

Btwenty

Cten twenty

DNone

Answer: Option A

Explanation:

From the main() method when the control comes to the display() method, we find that k is initialized with value 10, after which we see a switch-case statement.

The switch takes the argument or the choice as k, or 10.

Hence, case 10 gets executed, and we get the output as ten.

Workspace

NA
SHSTTON
259
Solv. Corr.
248
Solv. In. Corr.
507
Attempted
0 M:16 S
Avg. Time

4 / 64

Which Exception Will occur
class Test {
public static void main(String[ ] args) {
try {
String s = "5.6";
Integer.parseInt(s); // Cause a NumberFormatException
int i = 0;
int y = 2 / i;
System.out.println("Welcome to Java");
} catch (Exception ex) {
System.out.println(ex);
}
}
}

AWelcome to Java

BNumberFormatException

CException

DNone

Answer: Option B

Explanation:

String cannot be saved as interger


Workspace

NA
SHSTTON
146
Solv. Corr.
286
Solv. In. Corr.
432
Attempted
0 M:42 S
Avg. Time

5 / 64

Choose the correct option.

A programmer is designing a class to encapsulate the information about an inventory item.
A JavaBeans component is needed to do this.
The InventoryItem class has private instance variables to store the item information :

private int itemId;

Which method signature follows the JavaBeans naming standards for modifying the itemId instance variable ?


AitemId(int itemId)

Bupdate(int itemId)

CsetItemId(int itemId)

DmutateItemId(int itemI

EupdateItemId(int itemId)

Answer: Option C

Explanation:

Here is no explanation for this answer

Workspace

NA
SHSTTON
122
Solv. Corr.
332
Solv. In. Corr.
454
Attempted
0 M:0 S
Avg. Time

6 / 64

Choose the correct option.

Which interface does javutil.Hashtable implement?


AJavutil.Map

BJavutil.List

CJavutil.HashTable

DJavutil.Collection

Answer: Option A

Explanation:

The java.util.Hashtable class implements a hashtable, which maps keys to values.

To successfully store and retrieve objects from a hashtable, the objects used as keys must implement the hashCode() method and the equals() method.

Workspace

NA
SHSTTON
237
Solv. Corr.
236
Solv. In. Corr.
473
Attempted
0 M:21 S
Avg. Time

7 / 64

Choose the correct option.
class ArrayTest {
public static void main(String[] args) {
int[][] a1 = {{1,2,3},{4,5,6},{7,8,9,10}};
System.out.print(a1[0][2]+","+a1[1][0]+","+a1[2][1]);
}
}

APrints: 3, 4, 8

BPrints: 7, 2, 6

CRun-time error

DCompile-time error

Answer: Option A

Explanation:

In the given 2-dimensional array a1-

a1[0][2] = element in the first row and third column = 3

a1[1][0] = element in the second row and first column = 4

a1[2][1] = element in the third row and second column = 8

Hence, it prints 3,4,8.


Workspace

NA
SHSTTON
202
Solv. Corr.
197
Solv. In. Corr.
399
Attempted
1 M:51 S
Avg. Time

8 / 64

What will happen when you try to compile and run this code?
public class TGo implements Runnable{
 public static void main(String argv[]){
         TGo tg = new TGo();
         Thread t = new Thread(tg);
         t.start();
        }
        public void run() {
         while(true) {
   Thread.currentThread().sleep(1000);
                        System.out.println("looping while");
                }
        }
}

ACompilation and no output

BCompilation and repeated output of "looping while"

CCompilation and single output of "looping while"

DCompile time error

Answer: Option B

Explanation:

We will get a compile-time error in line no. 9, saying unreported exception InterruptedException; must be caught or declared to be thrown.

The sleep() method is responsible for generating the exception, and hence should be declared under try-catch block.

Hence, correct option is D.

Workspace

NA
SHSTTON
122
Solv. Corr.
269
Solv. In. Corr.
391
Attempted
0 M:46 S
Avg. Time

9 / 64

Choose the correct option.

A method is declared to take three arguments. A program calls this method and passes only two arguments. What is the result?


ACompilation fails.

BThe third argument is given the value null.

CThe third argument is given the value zero.

DAn exception occurs when the method attempts to access the third argument.

Answer: Option A

Explanation:

Compilation fails.

Workspace

NA
SHSTTON
143
Solv. Corr.
265
Solv. In. Corr.
408
Attempted
0 M:23 S
Avg. Time

10 / 64

What can directly access and change the value of the variable name?
package test;
class Target {
 public String name = "hello";
}

Aany class

Bonly the Target class

Cany class in the test package

Dany class that extends Target

Answer: Option C

Explanation:

First of all, the class is default access specifier.

Now, the features of a class with default access specifier is-

1. It can be accessed by same package subclass.

2. It can be accessed by same package non-subclass.

Apart from this, no other subclass or non-subclass of some other packages can access this class.

Workspace

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